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RideAnS [48]
3 years ago
7

How many electrons in an atom can share the quantum numbers n=2, l=1 and ml=1?

Chemistry
2 answers:
hoa [83]3 years ago
8 0

Answer : The number of electrons in an atom are, 2.

Explanation :

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from (-l\text{ to }+l). When l = 2, the value of m_l will be -2, -1, 0, +1, +2.

Spin Quantum number : It describes the direction of electron spin. This is represented as m_s The value of this is +\frac{1}{2} for upward spin and -\frac{1}{2} for downward spin.

As we are given that,  n=3,l=1,m_l=1

So,

m_s=+\frac{1}{2}\text{ and }-\frac{1}{2} (For each sub-shell)

From this we conclude that, m_l=1 that means there is one orbital that contains two electrons with opposite spin.

Hence, the number of electrons in an atom are, 2.

stepladder [879]3 years ago
6 0

There 2 electrons in an atom can share the quantum numbers n=2, l=1 and ml=1. The correct answer between all the choices given is the last choice. I am hoping that this answer has satisfied your query about and it will be able to help you.

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A sample of gas has an initial volume of 15 L and an initial pressure of 4.5 atm. If the pressure changes to 1.8 atm, what is th
olga_2 [115]

Answer:

37.5 L

Explanation:

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4 0
3 years ago
Read 2 more answers
You are asked to prepare 500 mL 0.300 M500 mL 0.300 M acetate buffer at pH 4.904.90 using only pure acetic acid ( MW=60.05 g/mol
defon

Answer:

You will need 9,0 g of acetic acid

Explanation:

The equilibrium acetate-acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka = 4,76

Using Henderson-Hasselbalch you will obtain:

pH = pka + log₁₀\frac{[A^{-}]}{[HA]}

Where HA is acetic acid and A⁻ is acetate ion

4,90 = 4,76 + log₁₀\frac{[A^{-}]}{[HA]}

1,38 = \frac{[A^{-}]}{[HA]} <em>(1)</em>

As acetate concentration is 0,300M:

0,300M = [HA] + [A⁻] <em>(2)</em>

Replacing (2) in (1):

[HA] = 0,126 M

And:

[A⁻] = 0,174 M

As you need to produce 500 mL:

0,5 L × 0,126 M = 0,063 moles of acetic acid

0,5 L × 0,174 M = 0,087 moles of acetate

To produce moles of acetate from acetic acid:

CH₃COOH + NaOH → CH₃COO⁻ + Na⁺ + H₂O

Thus, moles of acetate are equivalents to moles of NaOH and all acetates comes from acetic acid, thus:

0,087 moles of acetate + 0,063 moles of acetic acid  ≡ 0,15 moles of acetic acid ×\frac{60,05 g}{1mol} = <em>9,0 g of acetic acid</em>

<em></em>

I hope it helps!

5 0
3 years ago
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