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Setler [38]
3 years ago
9

N an algebra classroom, a teacher has created an estimation game using a jar of pennies. six students remain in the contest. eac

h student makes one guess and their guesses are as follows: 62, 52, 59, 42, 49, 65. one guess is 12 away from the exact number of pennies in the jar while the other guesses are 1, 4, 6, 9, and 11 pennies away. determine exactly how many pennies are in the guessing jar.
Mathematics
1 answer:
ella [17]3 years ago
6 0
Im guessing 35 all I did was add 12+11
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The scores of the first two football games were 28 and
butalik [34]

Answer:

35+28=63

Step-by-step explanation:

hope this helps

4 0
3 years ago
The weights of 83 randomly selected windshields were found to have a variance of 1.88. Construct the 95% confidence interval for
Morgarella [4.7K]

Answer:

95% confidence interval for the population variance = (1.42 , 2.62).

Step-by-step explanation:

We are given that the weights of 83 randomly selected windshields were found to have a variance of 1.88.

<em>So, firstly the pivotal quantity for 95% confidence interval for the population variance is given by;</em>

        P.Q. = \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2} __n_-_1

where, s^{2} = sample variance = 1.88

           \sigma^{2} = population variance

            n = sample of windshields = 83

So, 95% confidence interval for population variance, \sigma^{2} is;

P(58.85 < \chi^{2} __8_2 < 108.9) = 0.95 {As the table of \chi^{2} at 82 degree of freedom

                                              gives critical values of 58.85 & 108.9}

P(58.85 < \frac{(n-1)s^{2} }{\sigma^{2} } < 108.9) = 0.95

P( \frac{ 58.85}{(n-1)s^{2} } < \frac{1 }{\sigma^{2} } < \frac{108.9}{(n-1)s^{2} } ) = 0.95

P( \frac{ (n-1)s^{2}}{108.9 } < \sigma^{2} < \frac{ (n-1)s^{2}}{58.85 } ) = 0.95

<em><u>95% confidence interval for</u></em> \sigma^{2} = ( \frac{ (n-1)s^{2}}{108.9 } , \frac{ (n-1)s^{2}}{58.85 } )

                                                  = ( \frac{ (83-1)\times 1.88}{108.9 } , \frac{ (83-1)\times 1.88}{58.85 } )

                                                  = (1.42 , 2.62)

Therefore, 95% confidence interval for the population variance of the weights of all windshields in this factory is (1.42 , 2.62).

8 0
3 years ago
Evaluate the following logarithm Log 62,770
Cerrena [4.2K]

Answer:

The answer is 4.797752129

8 0
3 years ago
Find the perimeter. Simplify your answer.
Verizon [17]

Answer:

perimeter=32t units

Step-by-step explanation:

let:

a=8t-2

b=8t+2

<u>perimeter=2(a+b)</u>

<u>Subtitute values of a and b:</u>

=2(8t-2+8t+2)

=2(16t)

=<u>32t units</u>

7 0
3 years ago
Read 2 more answers
1.5.19
Fofino [41]

Answer:

I'm not sure what that U is for.

The answer is 459,461     These two do add to 920

Step-by-step explanation:

Remark

I'm going to make sure you are using consecutive odd numbers.

Let the smaller number = 2x - 1

Let the larger number = 2x + 1

Equation

2x - 1 + 2x + 1 = 920

4x = 920

x = 230

The consecutive numbers are 2*230 - 1 = 459

and 2*230 + 1                                             = 461

4 0
3 years ago
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