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balu736 [363]
3 years ago
7

Please help me with 10 and 11

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0

Answer:

10. 2x+y

11. x^2-15x+3

Step-by-step explanation:

10. when u add 7x+3y and 4x+4y you will get 11x+7y. 13x+8y minus 11x+7y will be 2x+y

11. when u add 3x^2+7x+1 and x^2-x+1 u will get 4x^2+6x+2. 5x^2-9x+5 minus 4x^2+6x+2 will be x^2-15x+3

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In the diagram below, line d is parallel to line c.
My name is Ann [436]

Answer:

85° = ∠x {corresponding angles}

∠x = ∠1 {vertically opp. angles}

And, ∠2 + 103° = 180° ( co-interior angles)

∠2 = 180° - 103°

∠2 = 77°

Now, m∠1 + m∠2 = 85° + 77°

= 162°

Hemce, option A. is the right answer.

6 0
2 years ago
One factor of the function f(x) = x3 − 8x2 + 17x − 10 is (x − 5). Describe how to find the x-intercepts and the y-intercept of t
kozerog [31]

Answer:

x-intercepts: (1,0), (2,0), (5,0)

y-intercepts: (0,-10)

Step-by-step explanation:

One factor of the function f(x) = x^3-8x^2 + 17x-10 is (x-5).

Factor the polynomial in the following way:

x^3-8x^2 + 17x-10\\ \\=x^3-5x^2-3x^2+15x+2x-10\\ \\=x^2(x-5)-3x(x-5)+2(x-5)\\ \\=(x-5)(x^2-3x+2)

Now factor the quadratic in brackets:

x^2-3x+2\\ \\=x^2-2x-x+2\\ \\=x(x-2)-(x-2)\\ \\=(x-2)(x-1)

Hence,

f(x)=(x-5)(x-2)(x-1)

The x-intercepts are points at which y = 0, so

(x-5)(x-2)(x-1)=0\\ \\x-5=0\ \text{or}\ x-2=0\ \text{or}\ x-1=0\\ \\x=5\ \text{or}\ x=2\ \text{or}\ x=1

The y-intercepts are points at which x = 0, so

y=0^3-8\cdot 0^2+17\cdot 0-10=-10

4 0
3 years ago
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If ac−b=1, which expression represents c?<br> i wil lmark you the brainliest
dolphi86 [110]

Answer:

The expression for c is

c =  \frac{b + 1}{a}

Step-by-step explanation:

The given equation is

ac - b = 1

To find an expression that represents,c we need to make c the subject.

Add b to both sides

ac = 1 + b

We now divide both sides by 'a'

\frac{ac}{a} =  \frac{b + 1}{a}

Simplify the LHS to get:

a=  \frac{b + 1}{a}

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3 years ago
Find the product. -2x(x^2 - 3)
gayaneshka [121]
(-2x)(x^2)+(-2x)(-3) = -2x^3 + 6x
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!!I’LL GIVE BRAINLIEST!! What additional information would you need to conclude that DE is the perpendicular bisector of AC?
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Answer:

The line AD is exactly between the line AC

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