the height of the house is
.
<u>Step-by-step explanation:</u>
Here we have , To estimate the height of a house Katie stood a certain distance from the house and determined that the angle of elevation to the top of the house was 32 degrees. Katie then moved 200 feet closer to the house along a level street and determined the angle of elevation was 42 degrees. We need to find What is the height of the house . Let's find out:
Let y is the unknown height of the house, and x is the unknown number of feet she is standing from the house.
Distance of house from point A( initial point ) = x ft
Distance of house from point B( when she traveled 200 ft towards street = x-200 ft
Now , According to question these scenarios are of right angle triangle as
At point A
⇒ 
⇒ 
⇒
..................(1)
Also , At point B
⇒ 
⇒
..............(2)
Equating both equations:
⇒ 
⇒ 
⇒ 
⇒ 
Putting
in
we get:
⇒
⇒ 
⇒ 
Therefore , the height of the house is
.
Answer:
b. -3
Step-by-step explanation:
9(2x+1) < 9x-18
(distribute the 9)
18x+9 <9x-18
(subtract 9 from both sides)
18x<9x-27
(subtract 9x from both sides)
9x<-27
(divide both sides by 9)
x<-3
Answer:
$-17.82
Step-by-step explanation:
he has $-17.82 because 30.85(the amount he has)-48.67(the amount he paid for) = -17.82
Answer:
b: only graph b is a function
Step-by-step explanation:
if you look closely graph a is in the middle of the boxes and all over the place, so the answer has to be b. Your welcome (pls give brainliest)
Answer:
The distance between 12m-sides is
.
Step-by-step explanation:
It is given that the parallelogram has sides 10m and 12m and an angle of 45°.
Draw an altitude from one 12m side to another 12 m side as shown in below figure.
The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.
Since angle C is acute angle therefore it must be 45 degree.








Therefore the distance between 12m-sides is
.