Question

A body of mass 10kg at rest is subjected force of 16N. Find the kinetic energy at end of 20s.​

Answer 1

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$\large \sf \underline{Problem:}$

• A body of mass 10kg at rest is subjected force of 16N. Find the kinetic energy at end of 20s.

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$\large \sf \underline{Answer:}$

$\huge \qquad \quad \sf{5,120 \: Joules}$

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$\large \sf \underline{Solution:}$

Firstly, find the acceleration:

• $\sf{A = F/m}$
• $\sf{A = 16N/10kg}$
• $\sf \pmb{A = 1.6m/s^2}$

Secondly, the velocity after 20 seconds will be:

• $\sf{V =u+at}$
• $\sf{V =0+1.6m/s^2(20s)}$
• $\sf \pmb{V =32m/s}$

Lastly, find the kinetic energy:

• $\sf{K=1/2mv^2}$
• $\sf{K=1/2(10)(32)^2}$
• $\sf{K=5(1024)}$
• $\sf{\underline{\underline{\pmb{K=5120\:J}}}}$

Hence, the kinetic energy at the end is 5,120 Joules.

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#LetEarthBreathe

Answer 2

$QUESTION:$

a body of mass 10kg at rest is subjected force of 16N. Find the kinetic energy at end of 20s.

$SOLUTION:$

$Given$ $that:$

• Mass = 10kg
• Initial Velocity (u) = 0
• Force = 16 N
• Time = 20 seconds

» Finding for the acceleration:

$a=F/m$

$a=16N/10kg$

$a=1.6/s^2$

» Then velocity after 20 seconds will be:

$v=u+at$

$v=0+1.6m/s^2(20s)$

$v=32/s^$

» Now , Finding for the kinetic energy:

$K=1*2mv^2$

$K=1/2(10)(32)^2$

$K=5(1024)$

$K=5120$ $J$

$ANSWER:$

• The kinetic energy aquired by the body is 5,120 Joules