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krok68 [10]
3 years ago
14

Write fraction as a decimal. 14/15

Mathematics
2 answers:
aleksklad [387]3 years ago
6 0
14\15 equals 9.3 repeating
laila [671]3 years ago
3 0
14.15 plz thx your welcoming me
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For all points on the y-axis of a coordinate grid, the x-coordinate is always?
vesna_86 [32]
Zero if it is talking about it is on the y-axis line
5 0
4 years ago
Need help with #8 and #10. Math. Rates.
Rzqust [24]
1.99/32=0.06 an oz
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3 0
4 years ago
What goes where. JdhshshHshxjancixd
valentina_108 [34]

Answer:

\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }

\boxed { \frac{3}{5}y } \to \: \boxed {y -  \frac{2}{5}y }

Step-by-step explanation:

We need to simplify

y +  \frac{2}{5}y

We collect LCM to get;

\frac{5y + 2y}{5}  =  \frac{7y}{5}

Therefore:

\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }

Also we need to simplify:

y -  \frac{2}{5}y

We collect LCM to get;

y -  \frac{2}{5}y =  \frac{5y - 2y}{5}  =  \frac{3}{5} y

Therefore

\boxed { \frac{3}{5}y } \to \: \boxed {y -  \frac{2}{5}y }

5 0
4 years ago
water enters a pool at an increasing rate given by W(t)=1+3t gallons per minute from t=0 to t=5 minutes. Find the amount of wate
Scorpion4ik [409]

The amount of water that has entered the pool over these five minutes is 42.5 gallons.

Given the rate at which water enter the pool W(t). To calculate the amount of water that has entered the pool over these five minutes, we integrate W(t) over the interval t = 0 to t = 5.

Amount\ of \ water=\int\limits^0_5 {W(t)} \, dt \\\\\\Amount\ of \ water=\int\limits^0_5 {(1+3t)} \, dt \\\\\\Amount\ of \ water=[t+1.5t^2]_0^5\\\\\\Amount\ of \ water=42.5\ gallons

The amount of water that has entered the pool over these five minutes is 42.5 gallons.

Find out more on integration at: brainly.com/question/23976638

4 0
3 years ago
What expression is equivalent to (2^3)^-5
aliya0001 [1]

Answer:

2^-15 or 1/2^15

Step-by-step explanation:

3*-5 is -15 so that makes it 2^-15

Apply the exponent rule a^-b = 1/a^b

That changes it to 1/2^15

Hope this helped! :)

7 0
4 years ago
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