Answer:

Step-by-step explanation:
p = Product of all odd integers between 500 an 598. So,
p = 501 x 503 x 505 ... x 595 x 597
q = Product of all odd integers between 500 and 602. So,
q = 501 x 503 x 505 ... x 595 x 597 x 599 x 601
From the above relations, we can see that q is equal to p multiplied by 599 and 601. i.e.
q = p x 599 x 601
or,

We need to evaluate 1p + 1q in terms of q. Using the value of p from above expression, we get:

jdjdus8sisiiwisjw eusheu2ikwa
Step-by-step explanation:
udusbwha8doeny1iwjdhs79osbxyaim2
Your answer is C :) blessings
1: Triple the quantity of a number “n” plus 4 equals 27. what would the expression look like?
[ Triple the quantity of a number “n” ] 3n
[ plus 4 ] + 4
[ equals 27 ] = 27
[ all together ] <u>3n + 4 = 27</u>
<u />
<u>Solving:</u>
[ given ] 3n + 4 = 27
[ subtract 4 from both sides ] 3n = 23
[ divide both sides by 3 ] n = 7 
2:Seventeen equals seven less than three times a number “n” what would the expression look like?
[ Seventeen equals ] 17 =
[ seven less than ] - 7
[ three times a number “n” ] 3n
[ all together ] <u>17 = 3n - 7</u>
<u />
<u>Solving:</u>
[ given ] 17 = 3n - 7
[ add 7 to both sides ] 24 = 3n
[ divide both sides by 3 ] 8 = n
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Step-by-step explanation:
you solve by using sqaure roots. hope this helps