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bezimeni [28]
4 years ago
13

1. Suppose you invest $500 at 10% interest, compounded annually. After 5 years, how much money would you have in your account? R

emember, the formula is A = P(1 + r)t.
2. If you invest $100 at 2% interest, compounded every 2 years, what would your balance be after 6 years?


4. Two friends are going on a road trip and are downloading podcasts to listen to on the drive. They choose two podcasts. They download A episodes of Podcast A, and B episodes of Podcast B. Each episode of Podcast A is x minutes long, and each episode of Podcast B is y minutes long. Tell what the following expressions represent in the situation.
a. Ax + By
b. A + B
Mathematics
1 answer:
Flura [38]4 years ago
6 0

Solution 1:

The compound interest formula to be used here is given by:

A=P(1+r)^{t}

Now we are given:

P=$500

r=10% or 0.1

t=5 years

Plugging them in the formula ,

A=500(1+0.1)^{5}

A=$802.255

Answer : After 5 years I will have $802.255 in my account.

Solution 2:

The formula for compound interest here is given by:

A=P(1+\frac{r}{n})^{nt}

Here interest is compounded after every two years, so n=2

r=2% or 0.02

t=6 years

P= $100

Plugging these into the formula:

A=100(1+\frac{0.02}{2})^{2*6}

A=100(1+0.01)^{12}

A=100(1.01)^{12}

A=$112.683

Answer: The balance after 6 years would be $112.683.

Solution 4:

In this situation:

a. Ax+By

Ax represents duration of Podcast A episodes

By represents duration of Podcast B episodes

Ax+By represents total duration of Podcast A and Podcast B songs.

b. A+B

A+B represents total number of episodes of Podcast A and Podcast B.

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Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and
ANEK [815]

Answer:

\frac{360000q}{359999}

Step-by-step explanation:

p = Product of all odd integers between 500 an 598. So,

p = 501 x 503 x 505 ... x 595 x 597

q = Product of all odd integers between 500 and 602. So,

q = 501 x 503 x 505 ... x 595 x 597 x 599 x 601

From the above relations, we can see that q is equal to p multiplied by 599 and 601. i.e.

q = p x 599 x 601

or,

p=\frac{q}{599 \times 601}

We need to evaluate 1p + 1q in terms of q. Using the value of p from above expression, we get:

p+q=\frac{q}{599 \times 601} + q\\\\ p+q=\frac{q+(599 \times 601q)}{599 \times 601}\\ \\ p+q=\frac{q(1+599\times601)}{599 \times 601}\\\\ p+q=\frac{360000q}{359999}

7 0
3 years ago
Which of the following has a removable discontinuity
dimaraw [331]

jdjdus8sisiiwisjw eusheu2ikwa

Step-by-step explanation:

udusbwha8doeny1iwjdhs79osbxyaim2

8 0
2 years ago
NEED HELP FAST
Natasha_Volkova [10]
Your answer is C :) blessings
5 0
3 years ago
1: Triple the quantity of a number “n” plus 4 equals 27. what would the expression look like?
Diano4ka-milaya [45]

1: Triple the quantity of a number “n” plus 4 equals 27. what would the expression look like?

[ Triple the quantity of a number “n” ] 3n

[ plus 4 ] + 4

[ equals 27 ] = 27

[ all together ] <u>3n + 4 = 27</u>

<u />

<u>Solving:</u>

[ given ] 3n + 4 = 27

[ subtract 4 from both sides ] 3n = 23

[ divide both sides by 3 ] n = 7 \frac{2}{3}

 

2:Seventeen equals seven less than three times a number “n” what would the expression look like?

[ Seventeen equals ] 17 =

[ seven less than ] - 7

[ three times a number “n” ] 3n

[ all together ] <u>17 = 3n - 7</u>

<u />

<u>Solving:</u>

[ given ] 17 = 3n - 7

[ add 7 to both sides ] 24 = 3n

[ divide both sides by 3 ] 8 = n

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=x2%20%3D%2017" id="TexFormula1" title="x2 = 17" alt="x2 = 17" align="absmiddle" class="latex-f
eduard

Step-by-step explanation:

you solve by using sqaure roots. hope this helps

5 0
4 years ago
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