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ella [17]
3 years ago
7

For all points on the y-axis of a coordinate grid, the x-coordinate is always?

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0
Zero if it is talking about it is on the y-axis line
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Simplify the expression where possible.<br><br> (-5x2)^3
Paul [167]

Answer:

-1000

Step-by-step explanation:

1. Do the Parenthesis problem first. (PEDMAS/PEMDAS)

You should then have -10^3

2. Solve with the exponent. (-10 x 10 x 10)

You should then get your final answer, which is -1000.

Any Questions/Concerns?

6 0
3 years ago
Which graph represents a function with a rate of change of 0.5?
Westkost [7]
It’s 5 because the other ones not important
3 0
2 years ago
-4+(-10t)/0.5+15
ziro4ka [17]
The answer is C because when you divide it out you get 6
6 0
2 years ago
Hana is playing a virtual reality game in which she must toss a disc to land on the largest triangular section of the board. If
svetoff [14.1K]

Answer:

Her probability of success is 1/2

Step-by-step explanation:

Firstly, we have to calculate the area of the entire board

That would be the rectangle of the measure 50 cm by 40 cm

We have the area as the product of this two

That would be 50 * 40 = 2,000 cm^2

Now, the value calculated is the area of the entire possible landing area

Secondly, we need to get the area that counts as a success

that would be the area of the triangle that has a base of 50 cm and a height of 40 cm

The area of this is the product of the two divided by 2

we have this as ;

50 * 40 * 1/2 = 1,000 cm^2

So, her probability of success is simply the area of the triangle divided by the area of the rectangle

= 1000/2000 = 1/2

8 0
3 years ago
PLEASE HELP!!! Find the equation , in the standard form of the line passing through the points (3,-4) and (5,1)
ExtremeBDS [4]
\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ 3 &,& -4~) &#10;%  (c,d)&#10;&&(~ 5 &,& 1~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies &#10;\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-4)}{5-3}\implies \cfrac{1+4}{5-3}\implies \cfrac{5}{2}&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{5}{2}(x-3)\implies y+4=\cfrac{5}{2}x-\cfrac{15}{2}

\bf y=\cfrac{5}{2}x-\cfrac{15}{2}-4\implies y=\cfrac{5}{2}x-\cfrac{23}{2}\impliedby &#10;\begin{array}{llll}&#10;\textit{now let's multiply both}\\&#10;\textit{sides by }\stackrel{LCD}{2}&#10;\end{array}&#10;\\\\\\&#10;2(y)=2\left( \cfrac{5}{2}x-\cfrac{23}{2} \right)\implies 2y=5x-23\implies \stackrel{standard~form}{-5x+2y=-23}&#10;\\\\\\&#10;\textit{and if we multiply both sides by -1}\qquad 5x-2y=23

side note:  multiplying by the LCD of both sides is just to get rid of the denominators
5 0
3 years ago
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