\left[y \right] = \left[ -5\right][y]=[−5] totally answer
Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
56 / 4 = 14
14 x 14 = 196 meters squared
:)
Answer:
19.7
Step-by-step explanation:
1. Change the percent to a decimal
0.41 of 48
2.Multiply the two numbers together.
0.41 of 48 = 19.68
3. Round to nearest tenth
19.68 = 19.70 = 19.7
