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4 years ago

What is the value of the digit nine in the number 197,184

Mathematics

1 answer:

Levart [38]4 years ago

6 0

The value of the digit nine in the number 197,184 is 90,000

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Suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.5

iris [78.8K]

Answer:

By the Empirical Rule, 99.7% of the students have grade point averages that are between 1.28 and 3.8.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 2.54

Standard deviation = 0.42.

Between 1.28 and 3.8?

1.28 = 2.54 - 3*0.42

So 1.28 is 3 standard deviations below the mean

3.8 = 2.54 + 3*0.42

So 3.8 is 3 standard deviations above the mean

By the Empirical Rule, 99.7% of the students have grade point averages that are between 1.28 and 3.8.

5 0

3 years ago

Read 2 more answers

What does x equal in x^3-9x+1=0

12345 [234]

X^3 -9x+1= 0 (minus 1)

X^3-9x=-1 (divide by 9)

x^3-x=-1/9

But it doesn’t work any further so you have written it wrong

5 0

3 years ago

Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side

maria [59]

Answer:

cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = $-\frac{1}{3}$

cos(b) = $-\frac{1}{4}$

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = $-\sqrt{1-(-\frac{1}{3})^2}$ [Since, sin(a) = $\sqrt{(1-\text{cos}^2a)}$ ]

= $-\sqrt{\frac{8}{9}}$

= $-\frac{2\sqrt{2}}{3}$

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be negative.

sin(b) = $-\sqrt{1-(-\frac{1}{4})^2}$

= $-\sqrt{\frac{15}{16}}$

= $-\frac{\sqrt{15}}{4}$

By substituting these values in the identity,

cos(a + b) = $(-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})$

= $\frac{1}{12}-\frac{\sqrt{120}}{12}$

= $\frac{1}{12}(1-\sqrt{120})$

= $\frac{1}{12}(1-2\sqrt{30})$

Therefore, cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

5 0

3 years ago

Find the quotient for 99diveded by 9,801

Makovka662 [10]

Answer:

Step-by-step explanation:

=> 9801/99 = 99

7 0

3 years ago

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suppose there is a 1.1 degree F drop in temperature every thousand feet that an airplane climbs into the sky. if the temp on the

Aleks04 [339]

For this case, the first thing we must do is define variables.

We have then:

x: altitude of the plane in feet

y: final temperature

The equation modeling the problem for this case is given by:

$y = - \frac{1.1}{1000} x + 59.7$

Thus, evaluating the function for x = 11,000 ft. Height we have:

$y = - \frac{1.1}{1000} (11000) +59.7$

$y = 47.6$

Answer:

the temperature at an altitude of 11,000 ft is 47.6 F

4 0

3 years ago

Read 2 more answers