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lions [1.4K]
2 years ago
6

Factor the expression using the GCF.

Mathematics
2 answers:
Nadya [2.5K]2 years ago
8 0

Answer:

4 , 2 , 5

Step-by-step explanation:

break down 8 an 20 to its simplest multiple factors 8 is 4 an 2 and 20 is 4 an 5 just plug them into box

olchik [2.2K]2 years ago
7 0

\mathbb{ANSWER:}\downarrow

\mathrm{4(2x+5y)}

\textsc{Explanation\::}

Use the GCF to factor this expression .

The GCF stands for :

\pmb{G} stands for Greatest

\pmb{C} stands for Common

\pmb{F} stands for Factor

\pmb{GCF} = Greatest Common Factor

<em>The abbreviation GCF comes in handy when it comes to factoring expressions like 8x+20y ( :</em>

The Greatest Common Factor of 8x+20y is 4 , so that's what we factor out :

4(2x+5y)

<em>Hint : Enter 4 , then 2 , then 5)</em>

<em />

<em />\footnotesize\textit{hope helpful ( :}

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Find the prime factors of 60 by dividing by prime numbers.​
Mars2501 [29]

Let's start with the smallest prime number 2

60/2 = 30

Divide that result over 2

30/2 = 15

We can't divide this by 2 because 15/2 = 7.5 isn't a whole number

Let's move onto 3

15/3 = 5

The result is a prime number, so we stop.

The values we divided as denominators were: {2, 2, 3}

We add the result 5 to the set to completely list all of the prime factors of 60

The prime factorization would be

<h3>60 = 2*2*3*5</h3>

which is the same as saying

<h3>60 = 2^2*3*5</h3>
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2 years ago
Question#1 Please simplify..
riadik2000 [5.3K]
Hey there,
6x + 5 (x-2)
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3 (-1) + 5 - 8(-1) + 1
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5 0
3 years ago
Brainliest if you are correct
frez [133]

Answer:

D) log_2(x)+3log_2(9)

Step-by-step explanation:

Given: log_2(9x^{3})

Use Exponent Rule: 3log_2(9x)

Use Addition Rule: log_2(x)+3log_2(9)

4 0
2 years ago
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Please solve and explain the question below
solong [7]

Answer:

OPTION A

Step-by-step explanation:

To find the table substitute the points on the given function and compare the values.

The given function is: $ y = x^2 + 2 $.

OPTION A:

(i) When x = -2

LHS = y = 6.

RHS = (-2)² + 2 = 4 + 2 = 6.

LHS = RHS

(ii) When x = -1

LHS = y = 3

RHS = (-1)² + 2 = 1 + 2 = 3.

LHS = RHS

(iii) When x = 0

LHS = y = 2

RHS = 0² + 2 = 2.

LHS = RHS

(iv) When x = 1

LHS = y = 3

RHS = (1)² + 2 = 1 + 2 = 3.

LHS = RHS

(v) When x = 2

LHS = y = 6

RHS = (2)² + 2 = 4 + 2 = 6

LHS = RHS

OPTION B:

(i) When x = -2

LHS = y = -2

RHS = (-2)² + 2 = 6

LHS \neq RHS

OPTION B is eliminated.

OPTION C:

(i) When x = -2

Using the same reason as OPTION B this option is eliminated as well.

So, OPTION A is the correct answer.

5 0
3 years ago
What is the opposite of real number
Dafna1 [17]

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A few examples of imaginary numbers: 3i, i, -7i, (√3)i, (1/2)i

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3 years ago
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