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Allushta [10]
2 years ago
7

The cost of the toy is expressed by the function y = 3x + 5, where x is the number of toys. If Peter bought 8 toys, find the cos

t of the toys.
Mathematics
1 answer:
Vika [28.1K]2 years ago
8 0

Answer: If Peter bought 8 toys, the cost of the toys will be 29.

From the equation, y = 3x + 5, they have given the value of x as eight. So if we put eight in the equation and solve it, we will get the value of y. I believe there are some errors in the question as it doesn't specify that y is the cost. Also cost requires some sort of unit, which is not given in the context. I can't really tell if it is dollars or rubles or pounds etc. So I just gave it as the way it is. Since no other clues are given, this is most likely it.

y = 3x + 5

y = 3(8) + 5

y = 24 + 5

y = 29


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Amanda exercised for 10 minutes every day in the first week, 20 minutes in the second week, 30 minutes in the third week, and 40
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1st week       10                   5
2nd week      20                  10 
3rd week       30                  20
4th week       40                  40
<span>
A) Amanda's method is linear because the number of minutes increased by an equal number every week.</span>
common difference is 10.
1st week      0 + 10 = 10
2nd week   10 + 10 = 20
3rd week    20 + 10 = 30
4th week    30 + 10 = 40

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5(2)^x

1st week   5(2⁰) = 5(1) = 5
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Read 2 more answers
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Answer:

3/2

Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\

Use \cot^2x=\csc^2x-1=\frac{1}{\sin^2x}-1

so

\cot^2(\frac{3\pi}{4}-\beta)=\frac{1}{\sin^2(\frac{3\pi}{4}-\beta)}-1 = \frac{1}{\frac{2}{5}}-1=\frac{5}{2}-1=\frac{3}{2}

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