Answer:
The distance from A to B is 736.2 to the nearest tenth foot
Step-by-step explanation:
In ΔCAB
∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A
∴ m∠CAD = m∠ACB + m∠ABC
∵ m∠ABC = 20°
∴ m∠ACB = 30° - 20° = 10°
We will use the sin rule to find the distance AB
∵ 
∴
≅ 736.2 to the nearest tenth foot
Answer:
C
Step-by-step explanation:
Answer:
someone had the same exact question i just helped him on it sub 4 for x and 1 for h
Step-by-step explanation:
Answer:
Option C
Step-by-step explanation:
Just took the quiz and it was right.