Hint: ![\bf \begin{array}{llll} sin^{-1}[sin(whatever)]= whatever\\\\ cos^{-1}[cos(whatever)]= whatever\\\\ tan^{-1}[tan(whatever)]= whatever \end{array}\\\\ ------------------\\\\ \begin{array}{llll} sin[sin^{-1}(whatever)]= whatever\\\\ cos[cos^{-1}(whatever)]= whatever\\\\ tan[tan^{-1}(whatever)]= whatever \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllll%7D%0Asin%5E%7B-1%7D%5Bsin%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Acos%5E%7B-1%7D%5Bcos%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Atan%5E%7B-1%7D%5Btan%28whatever%29%5D%3D%20whatever%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A------------------%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Asin%5Bsin%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Acos%5Bcos%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%5C%5C%5C%5C%0Atan%5Btan%5E%7B-1%7D%28whatever%29%5D%3D%20whatever%0A%5Cend%7Barray%7D)
Does anyone know this answer?
2 answers:
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Answer:
Not a factor because there is a remainder.
Step-by-step explanation:
Let's use synthetic division to solve this..
-1 ║ 2 | 4 | -2 | -8
║ | -2| -2 | 4
║ 2 | 2| -4 | -4
PS: if anyone knows a better way to do a synthetic division chart please let me know.