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Aneli [31]
3 years ago
7

Which functions have a y-intercept that is greater than the y-intercept of the function g(x) = |x 3| 4? check three options. f(x

) = –2 (x – 8)2 h(x) = –5 |x| 10 j(x) = –4(x 2)2 8
Mathematics
1 answer:
QveST [7]3 years ago
8 0

Using it's concept, it is found that the functions that have a greater y-intercept than g(x) = |x + 3| + 4 are given as follows:

  • h(x) = -5|x| + 10.
  • k(x) = 0.25(x - 4)² + 4.
  • m(x) = 0.25|x - 8| + 6.

<h3>What is the y-intercept of a function?</h3>

It is the <u>value of the function when the input is of zero</u>, that is, f(0).

For g(x) = |x + 3| + 4, we have that g(0) = 7. As for the other functions, we have that:

  • f(x) = -2(x - 8)² -> f(0) = -128.
  • h(x) = -5|x| + 10 -> f(0) = 10 -> Greater than g(x).
  • j(x) = -4(x + 2)² + 8 = f(0) = -8.
  • k(x) = 0.25(x - 4)² + 4 -> f(0) = 8 -> Greater than g(x).
  • m(x) = 0.25|x - 8| + 6 -> f(0) = 8 -> Greater than g(x).

More can be learned about the y-intercept of a function at brainly.com/question/24737967

#SPJ4

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What’s the y- intercept and x-intercept of y = 3/4x + 3
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Answer:

see below

Step-by-step explanation:

y = 3/4x + 3

To find the y intercept, let x =0 and solve for y

y = 0+3

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To find the x intercept, let y =0 and solve for y

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Calcula y comprueba las ecuaciones: porfavor alguienn la nesesito pliss a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8 = + 29
Alexeev081 [22]

Answer:

<u>a) x = 3</u>

<u>b) z = 10</u>

<u>c) p = 2</u>

<u>d) x = 7</u>

<u>e) u = 1</u>

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

<u>x = 3</u>

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

<u>z = 10</u>

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

<u>p = 2</u>

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

<u>x = 7</u>

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

<u>x = 1</u>

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

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