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Finger [1]
3 years ago
13

Can someone please help me

Mathematics
1 answer:
Katen [24]3 years ago
4 0
8. 0, 12,-45,-156.
 


9.

A. -27
B. -27,-19,-13,-5,4,0
C. 0
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15. What's the sum of 3/8 and 1/16?<br> 1/6 7/16 4/24 1/4
allsm [11]

Answer:

7/16

Step-by-step explanation:

1. you have to have the same denominator

7 0
3 years ago
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Need help with b and c
xz_007 [3.2K]

Answer:

Step-by-step explanation:

the formula is:

a_n = \frac{n+1}{n+2}

[tex]a_100 = \frac{101}{103}[\tex]

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3 years ago
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What is the length of segment AB?<br> Consider the diagram.<br> 7,9,18,25
Mrrafil [7]

Answer:

9

Step-by-step explanation:

It is congruent to the other side.

5 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
A cube has a side length of 6 cm. What is the volume of the cube, in cubic centimeters ​
Lady_Fox [76]

Answer:

V=216cm³

Step-by-step explanation:

V=216cm³

3 0
3 years ago
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