9514 1404 393
Answer:
D.) a+2b
Step-by-step explanation:
The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...
A) 3(0) = 0 . . . even
B) 1 +3 = 4 . . . even
C) 2(1+0) = 2 . . . even
D) 1 +2(0) = 1 . . . odd
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<em>Additional comment</em>
These rules apply to even/odd:
- odd × odd = odd
- odd × even = even
- even × even = even
- odd + odd = even
- odd + even = odd
- even + even = even
Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.
Answer:
Step-by-step explanation:
a). Given equation is y = 3x - 4
Table for the input-output values is,
x -1 0 1 2 3
y -7 -4 -1 2 5
Now we can plot these points on the graph (graph attached).
b). Equation is y = -2x + 3
Table for the input-output values will be,
x -1 0 1 2 3
y 5 3 1 -1 -3
Answer:8
Step-by-step explanation:
Answer:
ANY NUMBER THAT HAS A X BEHIND IT..
Examples
1x
7x
15803x
104762836297x
Answer:
455 or 680, depending
Step-by-step explanation:
If we assume the three choices are different, then there are ...
15C3 = 15·14·13/(3·2·1) = 35·13 = 455
ways to make the pizza.
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If two or three of the topping choices can be the same, then there are an additional ...
2(15C2) +15C1 = 2·105 +15 = 225
ways to make the pizza, for a total of ...
455 + 225 = 680
different types of pizza.
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There is a factor of 2 attached to the number of choices of 2 toppings, because you can have double anchovies and tomato, or double tomato and anchovies, for example, when your choice of two toppings is anchovies and tomato.
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nCk = n!/(k!(n-k)!)