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3 years ago

10

What is the volume of C? (The Triangular Prism)

1 answer:

Sloan [31]3 years ago

4 0

according to the pictures I have sent you can solve it! be successful

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Need help immediately

vekshin1

The answer is 6*square rooted*2

3 0

2 years ago

Determine if events A and B are mutually exclusive.

gladu [14]

Answer:

A) Not mutually exclusive

Step-by-step explanation:

Given

$P(A) = \frac{1}{4}$

$P(B) = \frac{3}{5}$

$P(A\ or\ B) = \frac{7}{10}$

Required

Determine if they are mutually exclusive or not

Mutually exclusive are defined by:

$P(A\ or\ B) = P(A) + P(B)$

So, we have:

$P(A\ or\ B) = \frac{1}{4} + \frac{3}{5}$

Take LCM

$P(A\ or\ B) = \frac{5+12}{20}$

$P(A\ or\ B) = \frac{17}{20}$

By comparing:

$P(A\ or\ B) = \frac{17}{20}$ ---- Calculated

$P(A\ or\ B) = \frac{7}{10}$ ---- Given

We can conclude that A and B are not mutually exclusive because:

$\frac{17}{20} \ne \frac{7}{10}$

6 0

2 years ago

There are 32 students in a class. Of the class, 3/8 of the students bring their own lunches. How many students bring their lunch

OverLord2011 [107]

Answer:

The number of students that bring their lunches is 12

Step-by-step explanation:

Let

x -----> the number of students that bring their lunches

y -----> the total number of students in a class

we know that

The number of students that bring their lunches divided by the total number of students in a class must be equal to 3/8

$\frac{x}{y}=\frac{3}{8}$

$x=\frac{3}{8}y$ -----> equation A

$y=32$ -----> equation B

substitute the value of y in equation A and solve for x

$x=\frac{3}{8}(32)$

$x=12$

therefore

The number of students that bring their lunches is 12

6 0

2 years ago

Complete the proof for proving that the diagonals of an isosceles trapezoid are congruent.

Alina [70]

..............................[a+b]2+c2

4 0

2 years ago

How do you solve it?

MatroZZZ [7]

Answer:

<em>i: </em>x=-2, x=1

<em>ii: </em>x=-1/2

Step-by-step explanation:

Quadratic form:

You solve <em>i </em>by using FOIL (First, Outside, Inside, Last) because it is a multiplication problem.

$(x+2)(x-1)=0$

<em>"first"</em> would be $x*x$ , which would equal $x^{2}$

<em>"outside"</em> would be $x*-1$ , which would equal $-1x, or -x$

<em>"inside"</em> would be $2*x$ , which would equal $2x$

<em>"last" </em>would be $2*-1$ , which would equal $-2$

Now you need to combine the terms so that they are one after the other

$x^{2}-x$ $+2x-2$

Combine like terms, and you should get:

$x^{2} +x-2$

i Solution

<em>You need to get the variable by itself.</em>

<em>Subtract two from both sides</em>

$x+2=0\\x=-2$

<em>Add one to both sides.</em>

$x-1=0\\x=1$

ii Solution

<em>Add all the terms.</em>

$x+2+x-1=0\\2x+1=0\\2x=-1\\x=-\frac{1}{2}$

8 0

3 years ago