Question

Please help ASAP

Answer 1

SOLUTION:

Let the length of the room = L = 12m

width of the room = b = 8m

Height of the room = h = 4m

• Area of the four walls of the room = Perimeter of the base x Height of the room.

$= 2(l + b) \times h = 2(12 + 8) \times 4$

$= 2 \times 20 \times 4 = 160 {m}^{2}$

• Cost of white washing per m² = ₹5

Hence , the total cost of white washing four walls of the room ;-

• ₹ ( 160 x 5 ) = ₹ 800

• Area of ceiling is 12 x 8 = 96m².

Cost of white washing the ceiling.

• ₹ (96 x 5 ) = ₹ 480.

So , the total cost of white washing ;

• ₹ ( 800 + 480 ) = ₹ 1280 .

Hope this helps you :)

#Carry on learning# :) ..