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Mnenie [13.5K]
3 years ago
10

Please awnser questions, no links, no I dont know 9.

Mathematics
2 answers:
dezoksy [38]3 years ago
8 0
I only see the store question but the answer is correct, 600
alukav5142 [94]3 years ago
4 0
It’s correct 600! Also try your best and keep your head up!
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Which term could be put into the blank to create a fully simplified polynomial written in standard form
podryga [215]

Answer:

x^{2} y^{2}

Step-by-step explanation:

7 0
3 years ago
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Sari's mom went to the store to buy some grapes,apples and bananas. The total mass of the fruit is 72kg. She bought 18kg of grap
il63 [147K]

Answer: 25kg

Step-by-step explanation:

18 + 29 = 47

72 - 47 = 25

She got 25kg of bananas.

4 0
3 years ago
What is the midpoint of the segment with two endpoints (4,-6) and (-2,-3)? Put your answers in decimal from, if applicable.
Ber [7]
Answer: 1,-4.5

Explanation: you can find this by finding the difference in y and the difference in x. The difference in x is -6, and the difference in y is +3. All you have to do after that is divide that by 2: -3,1.5, than add that to the first coordinate. That should be the midpoint.
4 0
2 years ago
Write the expression as one<br> involving only sin x and cos x.<br> sin 2x + cos x
AfilCa [17]

Answer:

sin 2x + cos x =  2 sin x cos x + cos x = (2 sin x + 1)cos x

Step-by-step explanation:

Given the expression: sin 2x + cos x,

then we can use the formula: sin 2x = 2 sin x cos x, which gives:

sin 2x + cos x =  2 sin x cos x + cos x = (2 sin x + 1)cos x

So there you have two expressions in terms of sin x and cos x, as requested. :D

6 0
2 years ago
find the equation of the line that is perpendicular to the given line and passes through the given point. CD; (-2,1). C cornet p
Studentka2010 [4]

Answer:

  x -2y = -4

Step-by-step explanation:

The slope of the line between points C and D is ...

  m = (y2 -y1)/(x2 -x1)

  m = (7 -13)/(5 -2) = -6/3 = -2

The slope of the perpendicular line is the opposite reciprocal of this: -1/(-2) = 1/2. The point-slope equation of the desired line is ...

  y -k = m(x -h) . . . . line with slope m through point (h, k)

  y -1 = 1/2(x -(-2))

We can rearrange this to standard form.

  2y -2 = x +2 . . . . . multiply by 2

  -4 = x -2y . . . . . . . subtract 2y+2

  x -2y = -4 . . . . . . standard form equation of the desired line

5 0
2 years ago
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