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2 years ago

PLEASE HELP THIS IS URGENT

Mathematics

1 answer:

Tom [10]2 years ago

3 0

Answer:

for #1 put a x for ABC. for #2 A and C for #3 AB

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The two triangles are similar. Determine the values of x, y, and z.

insens350 [35]

Answer:

y= 20 m

x= 15 m

z= 22 degree

Step-by-step explanation:

15+x=30 m

x=30-15

x= 15 m

z-18=40

z= 40-18

z= 22m

8 0

2 years ago

Please help me.........

marishachu [46]

Answer:

126 square feet

Step-by-step explanation:

The formula for the area of a triangle is ...

A = (1/2)bh . . . . . where b is the base length and h is the height

Here, you have a triangular face that has a base of 6 ft and a height of 14 ft. Its area is ...

A = (1/2)(6 ft)(14 ft) = 42 ft^2

The lateral area of the pyramid consists of 3 such triangles, so the lateral area is ...

LA = 3·(42 ft^2) = 126 ft^2

6 0

3 years ago

Use expressions for odd integers to confirm the conjecture that the product for two odd integers is an odd integer.

Mandarinka [93]

k, n - integers

2k+1 - an odd integer

2n+1 - another odd integer

The product of them:

(2k + 1)(2n + 1) =

= 4kn + 2k + 2n + 1 =

= 2(2kn + k + n) + 1

The product of integers (2kn) is integer

and the sum of them (2kn+k+n) also is integer

So (2k + 1)(2n + 1) = 2(2kn + k + n) + 1 is an odd integer

4 0

3 years ago

Devide 60 in the ratio of 2:3

nevsk [136]

Answer:

Let the amounts be 2x and 3x.

Then 2x+3x=60

So, 5x=60

So, x=60/5=12

So, amounts are

2x=2*12=24

And 3x=3*12=36

Hope this helps you!

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

3 years ago