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Virty [35]
2 years ago
15

write a growth/decay function to model the situation A car was purchased in 2000 for $22,500. It has depreciated at a rate of 5%

per year. What was the value of the car in 2011
Mathematics
1 answer:
AleksandrR [38]2 years ago
7 0

If the price of the car is $22,500 in 2000. Then the value of the car in 2011 with a decay of 5% every year is $12,798.

<h3>What is an exponent?</h3>

Exponential notation is the form of mathematical shorthand which allows us to write complicated expressions more succinctly. An exponent is a number or letter is called the base. It indicates that the base is to raise to a certain power. X is the base and n is the power.

A car was purchased in 2000 for $22,500.

It has depreciated at a rate of 5% per year.

Then the price of the car in 2011 will be

The decay function is modeled as

\rm A = P(1-r)^t

The number of years has been passed is 11.

Then we have

\rm A = 22,500(1-0.05)^{11}\\\\A = \$ \ 12798

More about the exponent link is given below.

brainly.com/question/5497425

#SPJ1

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Please help me with my math
gulaghasi [49]

Answer: The probability of choosing a green marble is \frac{1}{3}.

Step-by-step explanation:

  • 4 + 5 + 3 = 12 marbles <em>total.</em>
  • Since there are 4 green marbles, the probability of choosing one is \frac{4}{12}.
  • \frac{4}{12} simplified is \frac{1}{3}.

7 0
3 years ago
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What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
3 years ago
What is the area of a sector of a circle with a radius of 6 inches and formed by a central angle that measures 90°?
trapecia [35]

\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ \theta =90\\ r=6 \end{cases}\implies A=\cfrac{(90)(\pi )(6)^2}{360} \\\\\\ A=\cfrac{3240\pi }{360}\implies A=9\pi \implies A\approx 28.2743

8 0
4 years ago
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Can you help me plz in number 12,13,and 14 find the sum or difference.write your answer in simplest form plz explain good so I u
Maurinko [17]

Answer:

12. 11/18-1/6=4/9

13. 2/7+2/5=24/35

14. 3/4-3/10=9/20

Step-by-step explanation:

12. 11/18-1/6

11/18-1/6=11/18-(1/6)*(3/3)

11/18-1/6=11/18-(1*3)/(6*3)

11/18-1/6=11/18-3/18

11/18-1/6=(11-3)/18

11/18-1/6=8/18

Dividing the numerator and denominator of the fraction on the right side of the equation by 2:

11/18-1/6=(8/2)/(18/2)

11/18-1/6=4/9


13. 2/7+2/5

2/7+2/5=(2/7)*(5/5)+(2/5)*(7/7)

2/7+2/5=(2*5)/(7*5)+(2*7)/(5*7)

2/7+2/5=10/35+14/35

2/7+2/5=(10+14)/35

2/7+2/5=24/35


14. 3/4-3/10

3/4-3/10=(3/4)*(5/5)-(3/10)*(2/2)

3/4-3/10=(3*5)/(4*5)-(3*2)/(10*2)

3/4-3/10=15/20-6/20

3/4-3/10=(15-6)/20

3/4-3/10=9/20

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3 years ago
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Assoli18 [71]
The answer to the questions

4 0
4 years ago
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