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gladu [14]
3 years ago
11

If y=-12 when x=9 find y when x=-4

Mathematics
1 answer:
Monica [59]3 years ago
6 0

Answer:

16/3

Step-by-step explanation:

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Sam and Bruno were computing how many kilometers they rode in the 3 bike trips they took last month. In order, they rode 45.7, 4
Eddi Din [679]

Answer:

We are given number of miles the 3 bike trips they took last month = 45.7, 40.9, and 38 miles.

Sam and Bruno were computing how many kilometers.

Also one kilometer equals 0.621 miles.

From this we can see than 1 kilometer is smaller unit and a mile is a larger unit.

In order to convert number of miles into kilometers, we need to divide each number of mile by 0.621 miles.

We always divide a larger value by a smaller value to get the smaller unit.

Therefore,

Bruno is correct. When going from a larger unit to a smaller unit you need to divide.

Step-by-step explanation:

Hopefully this helped, if not HMU and I will get u a better answer.

<em>-Have a great day! :)</em>

4 0
3 years ago
Factor the expression:
Dovator [93]

Answer:

  B)  (4x-5i)(4x+5i)

Step-by-step explanation:

The expression can be treated as the difference of squares, and factored accordingly. That factoring is ...

  a² -b² = (a -b)(a +b)

__

Here, we have ...

  a² -b² = 16x² -(-25)

  a² = 16x²   ⇒   a = 4x

  b² = -25   ⇒   b = √-25 = 5i

Then the factoring is ...

  (a -b)(a +b) = (4x -5i)(4x +5i)

6 0
3 years ago
What is the value of y in the equation 4y – 2(1 – y) = –44?
LekaFEV [45]
Y=-7 use distributive property add like terms 


8 0
3 years ago
Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).
fomenos

Answer:

\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is 2a=|4--10|.

\implies 2a=|14|

\implies 2a=14

\implies a=7

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is (\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)

We need to use the relation a^2+b^2=c^2 to find b^2.

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

c=|6--3|=9

\implies 7^2+b^2=9^2

\implies b^2=9^2-7^2

\implies b^2=81-49

\implies b^2=32

We substitute these values into the standard equation of the hyperbola to obtain:

\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1

\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1

7 0
3 years ago
Help help help im stuck...
Trava [24]
N,R and T,U. Both are at 90 degree angles.
8 0
3 years ago
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