Answer:
f(a) = a^2 + 2a + 1
Step-by-step explanation:
Given the function f(x)= x^2 +2x + 1, find: f(a):
Merely substitute ' a ' for x:
f(a) = a^2 + 2a + 1
If you really want e*f(a), multiply the above by e:
e*f(a) = ea^2 + 2ea + e
6 consecutive even numbers...x, x + 2, x + 4, x + 6, x + 8, x + 10
x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 126
6x + 30 = 126
6x = 126 - 30
6x = 96
x = 96/6
x = 16
x + 2 = 16 + 2 = 18
x + 4 = 16 + 4 = 20
x + 6 = 16 + 6 = 22
x + 8 = 16 + 8 = 24
x + 10 = 16 + 10 = 26
ur numbers are : 16,18,20,22,24,26
Hey, this is really simple. Let's look at 12÷3 . That equals 4, since we have the zero from the 12 we need to add it to the four. So your answer would be 120÷3=40. Good luck !
there is no length in a circle
So you need to turn 5x^2 -3x -9 into 2x - 3.
Well first you need to take 5x^2 out by subtracting 5x^2 (-5x^2).
Then -3x needs to become 2x by adding 5x (+5x).
Finally -9 needs to become -3 by adding 6 (+6).
Put all the things you did together to make a polynomial.
-5x^2 + 5x + 6