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2 years ago

A B 21 48° 6x-24 D [?] << <[ ] 11 C

Mathematics

1 answer:

r-ruslan [8.4K]2 years ago

3 0

The shape in the figure is a composite shape with two triangles, and the inequality is 4 < x < 12

<h3>How to determine the range of value of x?</h3>

In the given figure, the side lengths AB and AD are equivalent.

This means that, we have the following angle relationship:

CAD < CAB

Substitute known values

6x - 24 < 48

Add 24 to both sides

6x < 72

Divide both sides by 6

x < 12

Also, we have the following angle relationship:

CAD > 0

Substitute known values

6x - 24 > 0

Add 24 to both sides

6x < 24

Divide both sides by 6

x < 4

This means that:

x < 4 and x < 12

Combine both inequalities

4 < x < 12

Hence, the inequality is 4 < x < 12

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Sheree’s brother gave samuel his collection of stamps when she left for college. at that time, the value of the collection was $

AlekseyPX

The rate of change of stamp collection was $57.5 per year.

Rate is comparison of two related quantities.

Often the second quantity is time (per second, per hour, etc) but it can be anything.

Can be in the style "this per that" or as a single number calculated using division.

Example: Sam makes 3 pancakes every 6 minutes, that is a rate of:

• 3 pancakes per 6 minutes

• 0.5 pancakes per minute

• 30 pancakes per hour

• an hourly rate of 30

By formula the rate of change = Change in cost/ Time taken

=( $980 - $420)/ 8years

= $460/ 8 years

= $57.5 per year

Thus the rate of change of stamp collection was $57.5 per year.

Learn more about rate here :

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1 year ago

Consider the following equation:

Sidana [21]

So you would plug in 0 for a from the beginning since this is numerical slope definition of a derivative

3 0

2 years ago

Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :