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ExtremeBDS [4]
2 years ago
14

Solve the inequality and graph the solution x +1 2/5 _< 6 8/10

Mathematics
1 answer:
mixer [17]2 years ago
6 0

Answer: x < 5 \frac{2}{5}

Step-by-step explanation:

x + 1 \frac{2}{5} < 6 \frac{8}{10}

x + 1 \frac{2}{5} < 6 \frac{4}{5}

x < 5 \frac{2}{5}

graph is attached

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Nikitich [7]

5 goes into 62 12 times with a remainder of 2. So technically 62 divided by 5 is 12.4.

Hope this helps!

6 0
4 years ago
Factor the algebraic expression. 40a+5
Vitek1552 [10]

Answer:

5 (8a + 1)

Step-by-step explanation:

Since they both can be factored by 5 you would divide both by 5 and get 8 and 1.

7 0
4 years ago
Exclude leap years from the following calculations. ​(a) Compute the probability that a randomly selected person does not have a
Scrat [10]

Answer:

a) 99.73% probability that a randomly selected person does not have a birthday on March 14.

b) 96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

c) 98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

d) 92.33% probability that a randomly selected person was not born in February.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

A non-leap year has 365 days.

​(a) Compute the probability that a randomly selected person does not have a birthday on March 14.

There are 365-1 = 364 days that are not March 14. So

364/365 = 0.9973

99.73% probability that a randomly selected person does not have a birthday on March 14.

​(b) Compute the probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

There are 12 months, so there are 12 2nds of a month.

So

(365-12)/365 = 0.9671

96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

​(c) Compute the probability that a randomly selected person does not have a birthday on the 31 st day of a month.

The following months have 31 days: January, March, May, July, August, October, December.

So there are 7 31st days of a month during a year.

Then

(365-7)/365 = 0.9808

98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

(d) Compute the probability that a randomly selected person was not born in February.

During a non-leap year, February has 28 days. So

(365-28)/365 = 0.9233

92.33% probability that a randomly selected person was not born in February.

6 0
3 years ago
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Sphinxa [80]

Answer:

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Step-by-step explanation:

To find the coterminal angles add / subtract 360°, that is

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Answer:

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Step-by-step explanation:

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