Answer:the answer is B
Step-by-step explanation:
Answer: 
Step-by-step explanation:
Given
The cylinder is 20 cm high
The radius of the cylinder is 
The total area of the figure is the sum of the rectangle and two circles
![\Rightarrow \text{Perimeter P=}2[h+2r]\\\Rightarrow P=2[20+6]\\\Rightarrow P=52\ cm](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ctext%7BPerimeter%20P%3D%7D2%5Bh%2B2r%5D%5C%5C%5CRightarrow%20P%3D2%5B20%2B6%5D%5C%5C%5CRightarrow%20P%3D52%5C%20cm)
The total area of the figure is

Answer:I think 0.4
Step-by-step explanation: Hope this helps
To do this we take the outlier off the parenthesis (the 4) and multiply it by the two numbers inside the parenthesis...
4*7 + 4*8
28+32
Answer:
m∠ABD = 88º
m∠CBD = 23º
Step-by-step explanation:
(-10x + 58) + (6x + 41) = 111
Combine like terms
-4x + 99 = 111
Subtract 99 from both sides
-4x = 12
Divide both sides by -4
x = -3
------------------------
m∠ABD = -10x + 58
m∠ABD = -10(-3) + 58
m∠ABD = = 30 + 58
m∠ABD = 88º
m∠CBD = 6x + 41
m∠CBD = 6(-3) + 41
m∠CBD = -18 + 41
m∠CBD = 23º