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2 years ago

Which of these points lie on the line described by the equation below?

Mathematics

2 answers:

nataly862011 [7]2 years ago

6 0

Answer:

Answer: A. (6, 4)

step by step

Alex777 [14]2 years ago

3 0

Answer:

Answer: A. (6, 4)

Equation of the line:

$y - 4 = - 2(x - 6) \\ y - 4 = - 2x + 12 \\ { \underline{y = - 2x + 16}}$

when x is 6:

$y = - 2(6) + 16 \\ y = - 12 + 16 \\ y = 4$

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3 years ago

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3 years ago

Solve the simultaneous equation y-2x+1=0 and 4x^2+3y^2-2xy=7

Lapatulllka [165]

The first equation is $y-2x+1=0$

$y=2x-1$ (Equation 1)

The second equation is $4x^{2}+3y^{2}-2xy=7$ (Equation 2)

Putting the value of x from equation 1 in equation 2.

we get,

$4x^{2}+3(2x-1)^{2}-2x(2x-1)=7$

$4x^{2}+3(4x^{2}+1-4x)-4x^{2}+2x=7$

by simplifying the given equation,

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Using discriminant formula,

$D=b^{2}-4ac$

$D=25-4 \times 6 \times -2 = 73$

Now the formula for solution 'x' of quadratic equation is given by:

$x=\frac{-b+\sqrt{D}}{2a} and x=\frac{-b-\sqrt{D}}{2a}$

$x=\frac{5+\sqrt{73}}{12} and x=\frac{5-\sqrt{73}}{12}$

Hence, these are the required solutions.

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3 years ago