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NemiM [27]
2 years ago
13

Write algebraic expressions to represent the following:

Mathematics
2 answers:
Alborosie2 years ago
6 0

Answer:

a) x + y

b) m x 7 or 7m

c) m x 3 or 3m

d) \frac{n - 3}{4}

Step-by-step explanation:

a) the sum of x and y

- the sum most likely always means addition

b) the product of m and 7

- the product usually means multiplucation

c) the cost of 3 movie tickets at m dollars each

- so your getting 3 movie tickets at $m

the total would be m + m + m which is the same as mutiplying m by 3

d) 3 less than n, all divided by 4

- 3 less than n

less than usually means subtraction

than divided by 4

andrey2020 [161]2 years ago
6 0

\rule{200}{2}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}

<em>             write algebraic expressions to represent the following:</em>

<em>a) the sum of x and y b) the product of m and 7</em>

<em>c) the cost of 3 movie tickets at m dollars each d) 3 less than n, all divided by 4</em>

<em />\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}

First, "the sum of" indicates that we add.

Since we're asked to find the sum of x and y, we need to add them:-

  • x+y

Now, the "product of" indicates that we multiply.

So we multiply m times 7, which can be written as follows:-

  • 7m

If we have 3 movie tickets, and each of them costs m dollars, then in order to find the cost of all 3 movie tickets, we need to find the product of the total number of tickets times the cost of one ticket:-

So we multiply 3 times m, or

  • 3m

Now, "3 less than n" indicates that we subtract 3 from n; this expression is divided by 4, or:-

  • \bold{\dfrac{3-n}{4}}

<h3>Good luck with your studies.</h3>

         \rule{200}{1}

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7 0
3 years ago
The number of girls in the Middle School Cyber Club was 6 more than double the number of boys, and in total there were 48 middle
Wittaler [7]

Answer:

g = number of girls;

b= number of boys

we know that: g= 6+2b

     and that: g+b= 156 kids in total

so we may write  g+b=(6+2b)+b=6+3b

                 but g+b= 156

so 6+3b = 156 => 3b= 156-6=150 =>   b=150/3=50 => b = 50 (number of boys)

g= 6+2b= 6+2 x 50= 106 => g =106 (number of girls)  

Step-by-step explanation:

5 0
3 years ago
If s is an increasing function, and t is a decreasing function, find Cs(X),t(Y ) in terms of CX,Y .
Sedbober [7]

Answer:

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

Step-by-step explanation:

Let's introduce the cumulative distribution of (X,Y), X and Y :

F(X,Y)(x,y)=P(X≤x,Y≤y)

  • FX(x)=P(X≤x)
  • FY(y)=P(Y≤y).

Likewise for (s(X),t(Y)), s(X) and t(Y) :

F(s(X),t(Y))(u,v)=P(s(X)≤u

  • t(Y)≤v)
  • Fs(X)(u)=P(s(X)≤u)
  • Ft(Y)(v)=P(t(Y)≤v).

Now, First establish the relationship between F(X,Y) and F(s(X),t(Y)) :

F(X,Y)(x,y)=P(X≤x,Y≤y)=P(s(X)≤s(x),t(Y)≥t(y))

The last step is obtained by applying the functions s and t since s preserves order and t reverses it.

This can be further transformed into

F(X,Y)(x,y)=1−P(s(X)≤s(x),t(Y)≤t(y))=1−F(s(X),t(Y))(s(x),t(y))

Since our random variables are continuous, we assume that the difference between t(Y)≤t(y) and t(Y)<t(y)) is just a set of zero measure.

Now, to transform this into a statement about copulas, note that

C(X,Y)(a,b)=F(X,Y)(F−1X(a), F−1Y(b))

Thus, plugging x=F−1X(a) and y=F−1Y(b) into our previous formula,

we get

F(X,Y)(F−1X(a),F−1Y(b))=1−F(s(X),t(Y))(s(F−1X(a)),t(F−1Y(b)))

The left hand side is the copula C(X,Y), the right hand side still needs some work.

Note that

Fs(X)(s(F−1X(a)))=P(s(X)≤s(F−1X(a)))=P(X≤F−1X(a))=FX(F−1X(a))=a

and likewise

Ft(Y)(s(F−1Y(b)))=P(t(Y)≤t(F−1Y(b)))=P(Y≥F−1Y(b))=1−FY(F−1Y(b))=1−b

Combining all results we obtain for the relationship between the copulas

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

7 0
3 years ago
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lora16 [44]

Answer:

Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2

Step-by-step explanation:

We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\

As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2

For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2

For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2

Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2

7 0
3 years ago
PLEASE HELP
ser-zykov [4K]

Answer:

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Step-by-step explanation:

i hope this works for you

7 0
3 years ago
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