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murzikaleks [220]
1 year ago
5

Help me out with this math problem for 50 points!!!

Mathematics
1 answer:
allsm [11]1 year ago
4 0

Answer:

2(5a+3b)+5a+2b

=10a+6b+5a+2b

=15a+8b

6y+2(3x+5)+2y+3

=6y+6x+10+2y+3

=8y+6x+13

8r+8r^2+6r^2+2r+r

=9r+14r^2

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How do you find the percent of a number
natulia [17]
You set up a proportion. first, put the percent so if it's 30 percent, it would be 30 over 100. Then, set up the second part. is over of. 
3 0
3 years ago
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Given the function f(x) in red, write the equation for the transformed function g(x)in green
STatiana [176]
g(x)=(x-4)^3-5

3 0
1 year ago
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Angelina_Jolie [31]
The unit rate you're trying to find is pages per day(or p/d), so the equation needs to have both a unit for pages and for days.
The equation we have is:
5,249 = 29d
If they read 5,249 <em>pages</em>, then we can include the unit for pages in the equation.
Since we also know that <em>d</em> is the number of days it took, you can replace <em>d</em> with days.
The equation becomes:
5,249\ pages=29*(x\days)
Now that we have one variable, we can solve for <em>p/d</em>:
\frac{5,249\ pages}{29}=x\ days\\\\181 = x
Thus it took them 181 days to read it all.

If Johnny read 5,249 pages over 181 days and the unit rate is pages per day(p/d), then the equation for finding <em>p/d</em> is:
\frac{p\ pages}{d\ days}=\frac{5,249\ pages}{181\ days}=\frac{29\ pages}{1\ day}\\\\29\ \frac{pages}{day}
Johnny read 29 pages per day.
8 0
2 years ago
Por favor denme una ecuación a esta pregunta:
Katena32 [7]

Answer:

x + 13 = 25

Step-by-step explanation:

Se puede representar "un número" con x.

x

"Adiciona" significa +.

x + 13

"El resultado" significa =.

x + 13 = 25

7 0
3 years ago
An electrical rm manufactures light bulbs that have a life span that is approximately normally distributed. The population stand
stira [4]

Answer:

The 't' test statistic = 1.46 < 1.69

The test of hypothesis is H 0 :μ = 800 is accepted

A sample of 30 bulbs are found came from average µ= 800

Step-by-step explanation:

Step 1:-

Given population of mean μ = 800

given size of small sample n =30

sample standard deviation 'S' = 45

Mean value of the sample χ = 788

Null hypothesis H_{0} =µ  =800

alternative hypothesis  H_{1} = µ ≠ 800

<u>Step 2</u>:-

The 't' test statistic t =  \frac{x-μ}{\frac{sig}{\sqrt{n} } }

                             t = \frac{788-800}{\frac{45}{\sqrt{30} } }

                       t = \frac{12}{8.215} = 1.4607

<u>Step 3</u>:-

The degrees of freedom γ = n-1 = 30-1 =29

From "t" value from table at 0.05 level of significance ( t = 1.69)

The calculated value t = 1.4607 < 1.69

Therefore The null hypothesis H_{0} ' is accepted.

<u>conclusion</u>:-

A sample of 30 bulbs are came found from average µ= 800

7 0
3 years ago
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