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Mathematics

1 answer:

djyliett [7]2 years ago

7 0

Answer:

Step-by-step explanation:

The lower value is 15,The upper value is 100, The median is 32 and 39, The lower quartile is 30, the upper quartile is 50, and the interquartile range is 36.

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Which statement is true about whether A and B are independent events? A and B are independent events because P(A∣B) = P(A) = 0.1

love history [14]

The events A and B are independent if the probability that event A occurs does not affect the probability that event B occurs.
A and B are independent if the equation P(A∩B) = P(A) P(B) holds true.
P(A∩B) is the probability that both event A and B occur.
Conditional probability is the probability of an event given that some other event first occurs.
P(B|A)=P(A∩B)/P(A)
In the case where events A and B are independent the conditional probability of event B given event A is simply the probability of event B, that is P(B).
Statement 1:A and B are independent events because P(A∣B) = P(A) = 0.12. This is true.
Statement 2:A and B are independent events because P(A∣B) = P(A) = 0.25.
This is true.
Statement 3:A and B are not independent events because P(A∣B) = 0.12 and P(A) = 0.25.
This is true.
Statement 4:A and B are not independent events because P(A∣B) = 0.375 and P(A) = 0.25
This is true.

5 0

3 years ago

Read 2 more answers

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$