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sdas [7]
2 years ago
9

Nick has 3 shirts: a white one, a black one, and a blue one. He also has two pairs of pants, one blue and one tan. What is the p

robability, if Nick gets dressed in the dark, that he winds up wearing the white shirt and tan pants? Show your work.
Mathematics
2 answers:
castortr0y [4]2 years ago
6 0
Well if he put the black shirt on you won’t be able to see him and that’s a fact
Vikki [24]2 years ago
5 0
There is a 1 out of 12, you could have a white shirt and blue pants and on and on with them all
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Solve -7x = -56<br> Help me
OleMash [197]
Easily done! Just do -56 divided by -7 but just remember two negatives equal a positive. So your answer would be 8!
8 0
3 years ago
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A rectangle has a height of 7x^2and a width of 3x^2+ 8x + 7.
Anika [276]

Answer:

Step-by-step explanation:

8 0
3 years ago
GEOMETRY PLEASE HELP!!! What is the surface area of the square pyramid shown if the height is 15 m?
Sindrei [870]

Answer:

The answer is 180 cm.......

4 0
3 years ago
Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).
Elan Coil [88]

Answer: \int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = \left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0

Then, replacing with point P and normal vector n:

36(x-5) + 20(y-0) + 45(z-0) = 0

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

z = \frac{180-36x-20y}{45}

When z = 0:

y = 9 + \frac{-9x}{5}

When z=0 and y=0:

x = 5

Then, triple integral is:

\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx

Calculating:

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx

\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0  {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx

\frac{1}{45} \int\limits^5_0  {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4}  } \, dx

\frac{1}{45} [30375-60750+118462.5-39150]

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0
3 years ago
write an equation of the line perpendicular to the given line that contains P in point slope form? P (4,-4) y=1/3x+4
11Alexandr11 [23.1K]

Answer: y+4=-3(x-4)

Step-by-step explanation:

- The equation of the line in point-slope form is:

y-y_1=m(x-x_1)

Where m is the slope and (x_1,y_1) is a point of the line.

- The equation of the line y=\frac{1}{3}x+4 is written is slope-intercept form, where the slope is \frac{1}{3}.

- By definition, when two lines are perpendicular to each other, the slopes are the negative reciprocals. Therefore, the slope of the perpendicular line must be -3.

- Substitute the point P and the slope -3 into the equation in point-slope form, therefore, you obtain:

y+4=-3(x-4)

4 0
3 years ago
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