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faust18 [17]
3 years ago
13

Pedro has a square practice net in his backyard. The diagonal of the net is 6 feet. Find the length of one side of the net.

Mathematics
1 answer:
olasank [31]3 years ago
5 0

Answer:

3sqrt2

Step-by-step explanation:

If a side length is a, then a^2 + a^2 = 36

2a^2 = 36

a^2 = 18

a = 3sqrt2

Or, you can remember that in a square, if you cut it in half diagonally, you get a 45-45-90 triangle, so the sidenglth is diagonal/sqrt2

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Step-by-step explanation:

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y - 3 = -2x + 2

y = -2x + 5

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5. Two vertices of a rectangle are (8,-5) and (8,7). If the area of the rectangle is 72 square units, name the possible location
Phantasy [73]

Answer:

<h3>#5</h3>

<u>Given vertices:</u>

  • (8, -5) and (8, 7)

These have same x-coordinate, so when connected form a vertical segment.

<u>The length of the segment is:</u>

  • 7 - (-5) = 12 units

The area of the rectangle is 72 square units, so the horizontal segment has the length of:

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<u>Possible location of the remaining vertices (to the left from the given):</u>

  • (8 - 6, -5) = (2, -5)

and

  • (8 - 6, 7) = (2, 7)
<h3>#6</h3>

<u>Similarly to previous exercise:</u>

  • (5, -8) and (5, 4) given with the area of 48 square units

<u>The distance between the given vertices:</u>

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<u>The other side length is:</u>

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<u>Possible location of the other vertices (to the right from the given):</u>

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and

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