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faust18 [17]
3 years ago
13

Pedro has a square practice net in his backyard. The diagonal of the net is 6 feet. Find the length of one side of the net.

Mathematics
1 answer:
olasank [31]3 years ago
5 0

Answer:

3sqrt2

Step-by-step explanation:

If a side length is a, then a^2 + a^2 = 36

2a^2 = 36

a^2 = 18

a = 3sqrt2

Or, you can remember that in a square, if you cut it in half diagonally, you get a 45-45-90 triangle, so the sidenglth is diagonal/sqrt2

You might be interested in
What is the equation for a slope of -3 and y intercept of 7
Tom [10]

Answer:

Step-by-step explanation:

y=-3+7

5 0
4 years ago
A manufacturing company produces valves in various sizes and shapes. One particular valve plate is supposed to have a tensile st
maxonik [38]

Answer:

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

p_v =2*P(z>1.413)=0.158  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

Step-by-step explanation:

Data given and notation  

\bar X=5.0611 represent the sample mean

\sigma=0.2803 represent the population standard deviation for the sample  

n=42 sample size  

\mu_o =5 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 5, the system of hypothesis would be:  

Null hypothesis:\mu = 5  

Alternative hypothesis:\mu \neq 5  

If we analyze the size for the sample is > 30 but and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>1.413)=0.158  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

8 0
4 years ago
Sasha sells T-shirts. Each day she earns a set amount, plus a commission.
WARRIOR [948]

Answer:

Domain → 0 < x < 5

Step-by-step explanation:

Sasha sells T-shirts and earns a fixed amount plus a commission by selling each shirt. (As given in the table)

Table attached shows a linear function (A regular increase in total pay with the increase in number of shirts sold)

So the input values of the table (Number of shirts sold) will represent the domain of the linear function.

Hence, reasonable domain for the function will be → 0 < x < 5

5 0
3 years ago
When y is 4, p is 0. 5, and m is 2, x is 2. If x varies directly with the product of p and m and inversely with y, which equatio
dmitriy555 [2]

Answer:

  \dfrac{xy}{pm}=8

Step-by-step explanation:

If x varies directly as the product of p and m, and inversely with y, the relation can be written ...

  x = k(pm)/y . . . . where k is the constant of proportionality

__

This can be solved for k:

  k = xy/pm

For the given values, the value of k is ...

  k = (2)(4)/((0.5)(2)) = 8

Then the relation between the variables can be written ...

  (xy)/(pm) = 8

5 0
2 years ago
From a group of six people, two individuals are to be selected at random. how many possible selections are there
Murrr4er [49]
You can do C(6,2) which gives 6*5/2 which is 15!
6 0
4 years ago
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