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garik1379 [7]
2 years ago
8

500 people are asked to name their favorite color. The results of this survey are shown in the pie chart below:

Mathematics
1 answer:
Gnom [1K]2 years ago
4 0
The answer would be the Blue sector.

Because 15% of 360° is 37.2

37.2 is only 2.8 away from 40 making it the closest!
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Find the absolute value.<br><br> 1 -31=___<br><br> -1 121=___<br><br> -1 -221=___
Veseljchak [2.6K]
I guess we will never know
5 0
2 years ago
Read 2 more answers
The average number of points a basketball team scored for
Ganezh [65]
Average is

(2x + X+6)/3=63
(2x+x+6)= 189
3x+6=189
3x=183 61

X=61
Scores for the game are: 61, 61, and 67
3 0
3 years ago
56,927.34 in expanded form
DanielleElmas [232]

Answer:

Step-by-step explanation:

Standard Form:

56,927.34

Expanded forms can be written like a sentence or stacked for readability as they are here.

Expanded Notation Form:

50,000  

+6,000  

+900  

+20  

+7  

+0.3

+0.04

Expanded Factors Form:

 5 ×10,000  

+ 6 ×1,000  

+ 9 ×100  

+ 2 × 0  

+ 7 ×1  

+ 3 ×0.1

+ 4 ×0.01

Expanded Exponential Form:

5 × 104

+ 6 × 103

+ 9 × 102

+ 2 × 101

+ 7 × 100

+ 3 × 10-1

+ 4 × 10-2

5 0
3 years ago
Read 2 more answers
What is the width of the vegetable garden?
MrRissso [65]

Answer:

The width of the vegetable garden is 3 feet.

Step-by-step explanation:

12 ÷ 4 = 3

8 0
3 years ago
The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c
valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is 10.4 \:cm^2

Step-by-step explanation:

The area of a rectangle with length L and width W is A= L\cdot W so the differential of <em>A</em> is

dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W

\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L so

dA=W\Delta L+L \Delta W

We know that each error is at most 0.1 cm, we have |\Delta L|\leq 0.1, |\Delta W|\leq 0.1. To find the maximum error in the calculated area of the rectangle we take \Delta L = 0.1, \Delta W = 0.1 and L=55, W=49. This gives

dA=49\cdot 0.1+55 \cdot 0.1

dA=10.4

Thus the maximum error in the calculated area of the rectangle is 10.4 \:cm^2

4 0
3 years ago
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