We can readily know the x^2-4x+4=3y then use it to replace the same function in the first equation which refers to the 3y+y^2-6y=0
y^2-3y=0
y(y-3)=0
y1=0 -----------y2=3
Answer:
Step-by-step explanation:
2q + 2p = 1 + 5q
-3q + 2p = 1
-3q = 1 - 2p
3q = 2p - 1
q = (2p -1)/3
Answer:
y = (x/(1-x))√(1-x²)
Step-by-step explanation:
The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:
x = r·cos(θ)
y = r·sin(θ)
x² +y² = r²
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r = sec(θ) -2cos(θ)
r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)
r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²
(x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations
x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor
y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)

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The attached graph shows the equivalence of the polar and rectangular forms.
Answer:
A) -1.7 x 10^-4 D)-0.00017
Step-by-step explanation:
Since its negative in the base B and C wont work. The negative in the exponent means the decimal moves left which exclude E.
Answer:
D. 
Step-by-step explanation:
There is a translation 1 point up along the y axis and a compression of 4.
Moving a function up (let's use <em>h</em> for the amount of points up) would change the function as so:

Meanwhile, the compression would modify x in this case. You can eliminate any answers (A. and B.) that have no modification to x, and eliminate C., as a fraction modification would actually widen the graph instead of compress it.
Hope this helps! :]