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2 years ago

What is the approximate circumference of the circle that has a center (3, 1) and passes through the point (3, 4)?

Mathematics

1 answer:

mr_godi [17]2 years ago

3 0

Step-by-step explanation:

You use the Distance Formula

d= √( x2 - x1 )^2 + ( y2 - y1 )^2

substitute

r= √(3-3)^2 + (4-1)^2

√0^2 + 3^2

r = √9

r = 3

Now you can use the equation for finding the circumference

2πr

2π3

≈ 6π or 18.85

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An object is translated by (x - 2; y- 6). If one point in the pre-image has the coordinates (-3, 7), what would be the

solong [7]

Answer:

(-5,1) would be the coordinates of its image

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3 years ago

What is the completely factored form of f(x) = 6x3 – 13x2 – 4x + 15?

masya89 [10]

We have to determine the complete factored form of the given polynomial

$f(x)=6x^3-13x^2-4x+15$ .

Let x= -1 in the given polynomial.

So, $f(-1)= 6(-1)^3-13(-1)^2-4(-1)+15 = -6-13+4+15 = 0$

So, by factor theorem

(x+1) is a factor of the given polynomial.

So, dividing the given polynomial by (x+1), we get quotient as $6x^2-19x+15$ .

So, $6x^3-13x^2-4x+15$ = (x+1) $6x^2-19x+15$ .

= $(x+1)(6x^2-10x-9x+15)$

= $(x+1)[ 2x(3x-5)-3(3x-5)]$

= $(x+1)(2x-3)(3x-5)$ is the completely factored form of the given polynomial.

Option D is the correct answer.

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3 years ago

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Ryan said that 212.314 73.243 285.557. Is Ryan's answer reasonable?

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3 years ago

Write the first three terms in the following sequences. Identify them as arithmetic or geometric

vaieri [72.5K]

Answer:

$A(1)=9$

$A(2)=4$

$A(3)=-1$

Arithmetic sequence

Step-by-step explanation:

We are given that

$A(n+1)=A(n)-5 \;for\;n\geq 1$ A(1)=9

We have to find first three terms and identify the sequence is geometric or arithmetic.

Substitute n=1

Then, we get

$A(2)=A(1)-5=9-5=4$

For n=2

$A(3)=A(2)-5=4-5=-1$

For n=3

$A(4)=-1-5=-6$

$d_1=A_2-A_1=4-9=-5$

$d_2=A_3-A_2=-1-4=-5$

$d_3=A_4-A_3=-6+1=-5$

$d_1=d_2=d_3=-5$

When the difference of consecutive terms are constant then the sequence is arithmetic sequence.

Therefore, given sequence is arithmetic sequence.

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3 years ago

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Ede4ka [16]

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