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lora16 [44]
2 years ago
12

If f(x)=x^2+2x-10 what is f(-2)

Mathematics
1 answer:
Finger [1]2 years ago
7 0

Answer:

-2

Step-by-step explanation:

f(2)= 2^2 + 2(2) - 10

= 4+4-10

=8-10

= -2

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The second term of a GP is 4, the fifth term is 81. Find the seventh term
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The seventh term of a G.P is

t_{7}  = 33,097.211

Step-by-step explanation:

<u><em>step(i):</em></u><em>-</em>

<em>Given the second term of a G.P is '4'</em>

<em>The general term of nth term is </em>

<em></em>t_{n}  = ar^{n-1}<em></em>

<em></em>t_{4}  = ar^{4-1} =4  

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<em>Also Given the fifth term of a G.P is '81'</em>

t_{5}  = ar^{5-1} =81

ar^{4} =81  …(ii)      

<u><em>Step(ii)</em></u>:-

<em>Dividing the equation (ii) divided by (i)</em>

<em />\frac{ar^{4} }{ar^{3} } = \frac{81}{4}<em />

<em>cancellation ' a' and 'r' terms , we get</em>

<em />r = \frac{81}{4}=20.25<em />

<em>substituting 'r' Value in equation (i), we get</em>

<em></em>ar^{3} =4<em></em>

a(\frac{81}{4}) ^{3} =4  

a = \frac{4X4X4X4}{(81)^{3} }= \frac{256}{531,441}

a = 0.00048

<u><em>Step(iii):-</em></u>

<u><em>The seventh term of G.P </em></u>

<em>The general term of nth term is </em>

<em></em>t_{n}  = ar^{n-1}<em></em>

<em></em>t_{7}  = (0.00048)(20.25)^{7-1}<em></em>

<em></em>t_{7}  = (0.00048)(20.25)^{6}= 33,097.211<em></em>

<em></em>

<em></em>

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