All categories

3 years ago

Best explained and correct answer gets brainliest.

Mathematics

1 answer:

Zolol [24]3 years ago

3 0

Your answer would be A because $4800 is your starting number and it increases 2% every year. How much is it in 20 years?

You use the formula ab^x
a is your starting number
b is the percentage
x is always the length of time

Since you are increasing and trying to get its worth larger than what it was before you use a number larger than one hundred percent in this case the number would be 1.02.

Y=4800(1.02)^20
Y=$7132.55

You might be interested in

On a given day 32 out of 220 people were selected for

Lena [83]

Answer:74

Step-by-step explanation: first you need to find the ratio so divide 220 by 32 to get 6.875 then didvide 510 by that same number and you will get 74. 18181818 but 74 because you can’t have a fraction of a person

7 0

3 years ago

Four students were discussing how to find the unit rate for a proportional relationship. Which method is valid?

LenKa [72]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Kendra was asked to find the number of students who planned to attend the evening symphony performance. She was told that 40 per

navik [9.2K]

Picture related to the question is attached below

Answer:

Kendra should have divided by 2 instead of multiplying by 2

Step-by-step explanation:

40 percent = percentage who plan to attend

100% = total percentage of student

From the question ;

When reducing percentages, division is employed and this the equation should be :

40/2 ÷ 100/2

40/2 * 2/100

20 * 1/50

20/50

= 0.4

0.4 * 50

= 20 students

6 0

3 years ago

Read 2 more answers

What is the average of the following numbers: 18, 64, 23, 78, 82, 91

Katen [24]

To Find The Answer, We Need To Add All Of Them Together, Then Divide By the Number Of Values. So:
64+23+78+82+91
-----------------------
5

<span>64+23+78+82+91 = 338.
</span>
338
-----
5

338/5 = 67.6

So, The Average Is 67.6

3 0

3 years ago

Use the given transformation to evaluate the given integral, where r is the triangular region with vertices (0, 0), (8, 1), and

Jlenok [28]

We first obtain the equation of the lines bounding R.

For the line with points (0, 0) and (8, 1), the equation is given by:

$\frac{y}{x} = \frac{1}{8} \\ \\ \Rightarrow x=8y \\ \\ \Rightarrow8u+v=8(u+8v)=8u+64v \\ \\ \Rightarrow v=0$

For the line with points (0, 0) and (1, 8), the equation is given by:

$\frac{y}{x} = \frac{8}{1} \\ \\ \Rightarrow y=8x \\ \\ \Rightarrow u+8v=8(8u+v)=64u+8v \\ \\ \Rightarrow u=0$

For the line with points (8, 1) and (1, 8), the equation is given by:

$\frac{y-1}{x-8} = \frac{8-1}{1-8} = \frac{7}{-7} =-1 \\ \\ \Rightarrow y-1=-x+8 \\ \\ \Rightarrow y=-x+9 \\ \\ \Rightarrow u+8v=-8u-v+9 \\ \\ \Rightarrow u=1-v$

The Jacobian determinant is given by

$\left|\begin{array}{cc} \frac{\partial x}{\partial u} &\frac{\partial x}{\partial v}\\\frac{\partial y}{\partial u}&\frac{\partial y}{\partial v}\end{array}\right| = \left|\begin{array}{cc} 8 &1\\1&8\end{array}\right| \\ \\ =64-1=63$

The integrand x - 3y is transformed as 8u + v - 3(u + 8v) = 8u + v - 3u - 24v = 5u - 23v

Therefore, the integration is given by:

$63 \int\limits^1_0 \int\limits^{1}_0 {(5u-23v)} \, dudv =63 \int\limits^1_0\left[\frac{5}{2}u^2-23uv\right]^{1}_0 \\ \\ =63\int\limits^1_0(\frac{5}{2}-23v)dv=63\left[\frac{5}{2}v-\frac{23}{2}v^2\right]^1_0=63\left(\frac{5}{2}-\frac{23}{2}\right) \\ \\ =63(-9)=|-576|=576$

6 0

3 years ago