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nata0808 [166]
2 years ago
11

Agree & disagree statements: CIrcles

Mathematics
1 answer:
likoan [24]2 years ago
6 0

Answer:

1. False

2. True

3. true

Step-by-step explanation:

The first answer is false, the second one is true and the third is true

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Ai dont nau bicas aim niu tu dis sait

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100 points please help 8th grade math
Irina-Kira [14]

Answer:B? l hope is B l hope helps

Step-by-step explanation:

if not help then l will answer other problem from you l hope is right

7 0
3 years ago
Andrew is selling tickets for the school play, and charges t dollars for adult tickets and 2 dollars for child tickets. On Monda
Andru [333]

Answer:

T=4 plz make brainlest answer

Step-by-step explanation:

Monday overall cost 36+5t

Tuesday overall cost 20+9t

36+5t=20+9t

-20 -20

16+5t =9t

-5t -5t

16=4t

t=4

Check

36+5t=20+9t (t=4)

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3 0
3 years ago
Thats the question ​
elixir [45]

Answer:

160 in ^2

Step-by-step explanation:

First we need to find the area of each shape and add them together

1. Triangles:

The formula for a triangle is (base x height)/2, so we can replace them as (5 * 4)/2 * 2( Because there are two triangles), so therefore the two triangles will add up to 20 inches

2. The Rectangles

<u>The Big Rectangle:</u>

The big rectangle is just <em>l x w </em> or 5 * 20 which is 100

<u>The small rectangle:</u>

To find the width of the small rectangle you have to do 20 - (5 + 5) because we are not including the triangles. 20 - (5 +  5) = 10, so that would be 10 * 4 = 40.

3.Add them together

20 + 100 + 40 = 160 inches ^2

Hope this helps!!!

4 0
3 years ago
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
4 years ago
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