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1 year ago

Agree & disagree statements: CIrcles

Mathematics

1 answer:

likoan [24]1 year ago

6 0

Answer:

1. False

2. True

3. true

Step-by-step explanation:

The first answer is false, the second one is true and the third is true

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Find the equation of the line

Butoxors [25]

Answer:

y= -1/3x + 5

Step-by-step explanation:

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2 years ago

Find f(1) if f(x)=5^x

dolphi86 [110]

Answer:

The value of function for x = 1 , y = 5 i.e f(1) is 5

Step-by-step explanation:

Given as :

f(x) = $5^{x}$

Now from the function the value of y depend on the value of x

So , for x = 1

I.e f(1) = $5^{1}$

Or, f(1) = 5

Hence The value of function for x = 1 , y = 5 i.e f(1) is 5 Answer

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3 years ago

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Dimas [21]

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3 years ago

Read 2 more answers

What is the equation of the following graph?

ser-zykov [4K]

Answer:

y=0.5x + 5

Step-by-step explanation:

The points are (0,5) and (-10,0)

to find the slope do

0-5/-10-0 = 5/10 = 1/2 = 0.5

next plug one of the points into point slope formula

y-y1=m(x-x1)

lets use the point (-10,0)

y1=0

x1= -10

m= 0.5

y-0=0.5(x- -10)

y = 0.5(x+10)

distribute the 0.5

y=0.5x+5

7 0

3 years ago

Which of the following are solutions to the equation below?

scoundrel [369]

Answer:

The correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Step-by-step explanation:

Given the expression

$x^2+10x+25=8$

Subtract 25 from both sides

$x^2+10x+25-25=8-25$

Simplify

$x^2+10x=-17$

Add 25 or 5² to both sides

$x^2+10x+5^2=8$

$x^2+10x+5^2=\left(x+5\right)^2$

so the expression becomes

$\left(x+5\right)^2=8$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x+5=\sqrt{8}$

Subtract 5 from both sides

$x+5-5=2\sqrt{2}-5$

$x=2\sqrt{2}-5$

solve

$x+5=-\sqrt{8}$

Subtract 5 from both sides

$x+5-5=-2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Therefore, the solution to the equation

$x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5$

Hence, the correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

6 0

3 years ago