Answer: The answer is 43.5 because when using the formula you get this result.
Step-by-step explanation: Area of triangle is base x height divided by 2. So do our base 14.5 and our height 6 and multiply them together. 14.5 x 6 = 87 / 2 = 43.5
Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
If you look at the attached graphic, you will see that the altitude (or height) of an equilateral triangle is:
Height = side length * sq root (3) / 2
Area = side^2 * sq root (3) / 4
10 over the power of negative 4
The first A because once you plug in the numbers into the x,y it is easier to find the solution.