We have that
point C and point D have y = 0-----------> (the bottom of the trapezoid).
point A and point B have y = 4e ---------- > (the top of the trapezoid)
the y component of midpoint would be halfway between these lines
y = (4e+ 0)/2 = 2e.
<span>the x component of the midpoint of the midsegment would be halfway between the midpoint of AB and the midpoint of CD.
x component of midpoint of AB is (4d + 4f)/2.
x component of midpoint of CD is (4g + 0)/2 = 4g/2.
x component of a point between the two we just found is
[(4d + 4f)/2 + 4g/2]/2 = [(4d + 4f + 4g)/2]/2 = (4d + 4f + 4g)/4 = d + f + g.
</span>therefore
the midpoint of the midsegment is (d + f + g, 2e)
Answer:
D
Step-by-step explanation:
Answer:
200
Step-by-step explanation:
the above is an arithmetic progressions
number of terms of an AP = a+( n -1 )d
a= first term= 8
d= common difference= 12-8= 4
49th term:
= 8+(49-1)4
= 8+(48)4
= 8+192= 200
therefore, the 49th term is 200
Answer:
Give Full Question ...I think this question is incomplete
160/140 = x/56
cross multiply
(140)(x) = (160)(56)
140x = 8960
x = 8960/140
x = 64 lbs <== Vince's weight on the other planet