Question

What is the exact value of the other root?

Answer 1

The exact value of the other root to the quadratic equation is $x = -2 - \sqrt 6$

How to express the solution?

One of the root is given as:

$x = -2 - \sqrt 6$

As a general rule, the solution to a quadratic equation is represented by:

$x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

This means that the actual root of the given root is:

$x = -2 \pm \sqrt 6$

Split the equation

$x = -2 - \sqrt 6$ and $x = -2 + \sqrt 6$

Hence, the exact value of the other root to the quadratic equation is $x = -2 - \sqrt 6$

Read more about quadratic equations at:

brainly.com/question/8649555

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