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Ainat [17]
3 years ago
13

A daycare center needs a profit of $600

Mathematics
1 answer:
Rainbow [258]3 years ago
6 0
A daily profit for an average work place-
About 300
Math~
<$600> 300=daily.
(5x11)=(6*52
12,40'•52,090
0.40
-----
/o/dec/40/Tenths
Keep in mind the 300 ^
BOX the important #'s which are:
2,11,17,80,40,44,63,and 88

(300-200=100)+(100x6)+(-)=600

88♡-(50+300)
(♡ this symbol marks the important #'s (KEEP IN MIND))

6:0/(500)+60**1200
1200•<600> €cp=1200-600=?
(600-17♡+800x<300> thê âvêrâgê

next

^^^^^^^^^^^
¥A+5k (5,000)=?
[1200(+9)=1209<600>=609+10,000(10,609]

Those are many ways to solve this problem
I hope this helped♡
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Morgarella [4.7K]

Answer:

f'(x)=-\frac{2}{x^\frac{3}{2}}

Step-by-step explanation:

So we have the function:

f(x)=\frac{4}{\sqrt x}

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The definition of a derivative as a limit is:

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Therefore, our derivative would be:

\lim_{h \to 0}\frac{\frac{4}{\sqrt{x+h}}-\frac{4}{\sqrt x}}{h}

First of all, let's factor out a 4 from the numerator and place it in front of our limit:

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Place the 4 in front:

=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}

Now, let's multiply everything by (√(x+h)(√(x))) to get rid of the fractions in the denominator. Therefore:

=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}(\frac{\sqrt{x+h}\sqrt x}{\sqrt{x+h}\sqrt x})

Distribute:

=4\lim_{h \to 0}\frac{({\sqrt{x+h}\sqrt x})\frac{1}{\sqrt{x+h}}-(\sqrt{x+h}\sqrt x)\frac{1}{\sqrt x}}{h({\sqrt{x+h}\sqrt x})}

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=4 \lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }

Now, multiply both sides by the conjugate of the numerator. In other words, multiply by (√x + √(x+h)). Thus:

= 4\lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }(\frac{\sqrt x +\sqrt{x+h})}{\sqrt x +\sqrt{x+h})}

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Simplify the numerator:

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Simplify:

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Multiply across:

= \frac{-4}{(2x\sqrt{x})}

Reduce. Change √x to x^(1/2). So:

=-\frac{2}{x(x^{\frac{1}{2}})}

Add the exponents:

=-\frac{2}{x^\frac{3}{2}}

And we're done!

f(x)=\frac{4}{\sqrt x}\\f'(x)=-\frac{2}{x^\frac{3}{2}}

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