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bezimeni [28]
2 years ago
12

39-42 Differentiate

la"> and find the domain of f\text{.}
40. f(x)=\ln \left(x^{2}-2 x\right)
Mathematics
1 answer:
MAVERICK [17]2 years ago
4 0

\text{Given that,}\\\\f(x) = \ln (x^2 - 2x)\\\\f'(x) = \dfrac  1{x^2 -2x} \cdot (2x - 2) = \dfrac{2(x-1)}{x(x-2)}\\\\\\\text{domain f(x): }   \{x| x < 0, x > 2 \}

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Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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barX=37.465 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=2.27 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

barX +- t*[(s)/(sqrt{n))]   (1)

In order to calculate the critical value t we need to find first the degrees of freedom, given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that t_(alpha/2)=2.26

Now we have everything in order to replace into formula (1):

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37.465+2.26[(2.27)/(sqrt{10))]=39.1

So on this case the 95% confidence interval would be given by (35.9;39.1)    

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