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docker41 [41]
2 years ago
7

PLS HELP

Mathematics
1 answer:
user100 [1]2 years ago
7 0

Answer:

I just answered this in the other equal post.

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Convert from scientific notation to standard form 4.83 x 10^-3
ANTONII [103]

4.83 x 10^-3 can be re-written in standard form by moving the decimal point 3 units to the left:   0.00483.

Note:  If you want to be mathematically correct, please write 10^(-3), not 10^-3.  If the exponent is +, you don't need the parentheses.


5 0
3 years ago
Acute isosceles<br> obtuse isosceles<br> acute scalene<br> equiangular equilateral
zhenek [66]

Answer:

obtuse isosceles

Step-by-step explanation:

isosceles angles

7 0
2 years ago
Find the slope of the line. <br><br> A. 1/3<br> B. - 1/3<br> C. 3<br> D. -3
BARSIC [14]

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (0, -2) and (6, 0).

Substitute:

m=\dfrac{0-(-2)}{6-0}=\dfrac{2}{6}=\dfrac{1}{3}

<h3>Answer: A. 1/3</h3>
3 0
2 years ago
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
Jobisdone [24]

Answer:

f(x)=x^4-9x^2-50x-150

Step-by-step explanation:

Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).

By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.

Therefore the polynomial in factored form is f(x)=(x-5)(x+3)(x-(-1+3i))(x-(-1+3i))

We expand to get:f(x)=(x^2-2x-15)(x^2+2x+10)

We expand further to get:\

f(x)=x^4-9x^2-50x-150

3 0
3 years ago
Write each fraction as the sum of a whole number and a fraction less than 1
Tpy6a [65]

Given:

The fractions are:

\dfrac{6}{5},\dfrac{11}{7},\dfrac{21}{4}

To find:

The each fraction as the sum of a whole number and a fraction less than 1.

Solution:

The given fraction is \dfrac{6}{5}.

\dfrac{6}{5}=\dfrac{5+1}{5}

\dfrac{6}{5}=\dfrac{5}{5}+\dfrac{1}{5}

\dfrac{6}{5}=1+\dfrac{1}{5}

Therefore, the given fraction \dfrac{6}{5} can be written as 1+\dfrac{1}{5}.

The given fraction is \dfrac{11}{7}.

\dfrac{11}{7}=\dfrac{7+4}{7}

\dfrac{11}{7}=\dfrac{7}{7}+\dfrac{4}{7}

\dfrac{11}{7}=1+\dfrac{4}{7}

Therefore, the given fraction \dfrac{11}{7} can be written as 1+\dfrac{4}{7}.

The given fraction is \dfrac{21}{4}.

\dfrac{21}{4}=\dfrac{20+1}{4}

\dfrac{21}{4}=\dfrac{20}{4}+\dfrac{1}{4}

\dfrac{21}{4}=5+\dfrac{1}{4}

Therefore, the given fraction \dfrac{21}{4} can be written as 5+\dfrac{1}{4}.

7 0
2 years ago
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