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castortr0y [4]
3 years ago
10

If we wanted to know how high a 5th-grade student could jump, how many students would be reasonable to test? 5, 12, 30, or 200.

Mathematics
1 answer:
77julia77 [94]3 years ago
4 0
The right amount to test would be 30.

200 is to many kids and 12 is not enough.

Hope this Helps!!
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Aneli [31]

Answer:

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Step-by-step explanation:

7 0
3 years ago
A 12 ounce can of store brand tomato paste costs $1.46 at a supermarket. The unit price of the sauce is listed on the shelf belo
kykrilka [37]
You can calculate it by divided but most of the people get confused about is it gonna be 12/1.46 or 1.46/12. The correct is 1.46/12 because take the money divided all 12 to get a unit price if you take 12/1.46 which mean divided all ounce can to money and that makes nonsense.


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4 0
3 years ago
A square has an area of 576 great inches how long is each side of feet
bija089 [108]
The formula for the area of a square is A=s*s or A=s^2
So we can plug in the area and solve for the side
576=s^2 (square root both sides)
s=24 inches

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Hope this helps
6 0
2 years ago
Read 2 more answers
The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

4 0
3 years ago
Mr. Sen wants to treat a group of friends either to the movies or to a hockey game for his birthday. Both the theater and the ho
monitta

Answer:

there's no numbers to answer this question

Step-by-step explanation:

I apologize but all the information and table is gone there is no way to answer this for you

8 0
2 years ago
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