All categories

2 years ago

Which function has the same minimum value as ? f(x) = 3x 3 f(x) = |x| 3 f(x) = –x2 3

Mathematics

1 answer:

Likurg_2 [28]2 years ago

4 0

The function that has the same minimum value as fx= 3x³ is f(x) = x + 3.

<h3>What is a function?</h3>

It should be noted that a function simply means a relation or expression that involves two or more variables.

In this case, the function that has the same minimum value as the expression of 3x³ is f = x + 3.

Learn more about functions on:

brainly.com/question/2833285

#SPJ4

You might be interested in

One of the characteristics of legal English is _____.

LenKa [72]

One of the characteristics of legal English is archaic English words.
Usually, in legal texts you would use words that aren't normally used in everyday speech, in order to show the importance and formality of that document.

6 0

2 years ago

Read 2 more answers

Which are linear pairs? Check all that apply

Kaylis [27]

Answer:

the <em>last one</em> (<u><em>CAE & BAD</em></u>) is the only Linear pair!

Hope this Helps! <3

6 0

1 year ago

What is the value of the expression?

gulaghasi [49]

The answer is fourteen

3 0

2 years ago

Carolyn paid a mechanic x dollars per hour for a 5-hour job plus $70 for parts. The total charge was less than $320. Which equat

snow_lady [41]

Answer: should be 70+50x is less than 320

Step-by-step explanation:$70 is only added once, and for 5 hours, she pays him a certain amount of $(x). I don't know if the multiple choices are valid

3 0

2 years ago

SHOW YOUR WORK, <br><br>PLEASE HELP!!!!!!!!!

Shkiper50 [21]

To find the inverse, we swap the variables y and x, then solve for the new y.

3a. $y=\frac{3}{x-1}$

Swapping the variables: $x=\frac{3}{y-1}$
Solving for y: $x(y-1)=3 \\ y-1= \frac{3}{x} \\ y=1+\frac{3}{x}$
The domain of this inverse is $x ≠ 0$ .
3b. $y=x^2-1$

Swapping: $x = y^2 - 1$
Solving for y: $y^2 = x + 1 \\ y = \sqrt{x+1}$
The domain of this inverse is $x ≥ -1$ .
3c. $y=\sqrt[3]{\frac{x-7}{3}}$
Swapping: $x=\sqrt[3]{\frac{y-7}{3}}$
Solving for y: $x^3=\frac{y-7}{3} \\ y-7=3x^3 \\ y=3x^3+7$
The domain of this inverse is all real numbers.
4a. $y=\frac{3}{x-1}$ , $y=1+\frac{3}{x}$
$y=\frac{3}{(1+\frac{3}{x})-1} \\ y=\frac{3}{(\frac{3}{x})} \\ y=x$
$y=1+\frac{3}{(\frac{3}{x-1})} \\ y = 1+(x-1) \\ y = x$

4c. $y=\sqrt[3]{\frac{x-7}{3}}$ , $y=3x^3+7$
$y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x$
$y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x$

3 0

3 years ago