Question

1. the height of a right triangular prism is inches. each side of the triangular base measures 10 inches, and the height of the base is inches. the triangular prism is placed atop a cube whose side measures 10 inches so that one of the triangular prism’s bases lies completely on one side of the cube. what is the surface area of the solid formed?

Answer 1

The surface area of the solid formed by the triangular prism and cube will be 598.33 square inches.

What is a prism?

A prism is a closed solid that has two parallel bases connected by a rectangle surface.

The height of a right triangular prism is 11/6 inches.

Each side of the triangular base measures 10 inches, and the height of the base is 26/3 inches.

The triangular prism is placed at top of a cube whose side measures 10 inches so that one of the triangular prism’s bases lies completely on one side of the cube.

Then the surface area of the prism will be

$\rm Surface \ area = 5 \times (10 \times 10) + 0.5 \times 10 \times \dfrac{26}{3} + 3 \times 10 \times \dfrac{11}{6}\\\\\\Surface \ area = 598.33\ in^2$

More about the prism link is given below.

brainly.com/question/12649592