What is the equation of the line that passes through the point (-6,3)(−6,3) and has a slope of -4/3?
1 answer:
The equation of the line that passes through the point (-6,3) and has a slope of -4/3 is y=(-4/3)x-5.
<h3>What is the equation of a line?</h3>A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,
y =mx + c
where,
x is the coordinate of the x-axis,
y is the coordinate of the y-axis,
m is the slope of the line, and
c is constant.
Given the slope of the line is -4/3, also, the line passes through the point (-6,3). Therefore, when the values are substituted in the general equation of a line to get the value of the constant, we will get,
y = mx + c
3 = (-4/3)(-6)+c
3 = 8 + c
c = -5
Thus, the equation can be written as y=(-4/3)x-5.
Hence, the equation of the line that passes through the point (-6,3) and has a slope of -4/3 is y=(-4/3)x-5.
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