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kykrilka [37]
3 years ago
15

List the single-digit divisors of 2100. I really need help

Mathematics
1 answer:
liberstina [14]3 years ago
5 0

Answer:

  • 1, 2, 3, 4, 5, 6, 7

Step-by-step explanation:

<u>Prime factors of 2100 are:</u>

  • 2100 = 2*2*3*5*5*7

<u>The single-digit divisors are:</u>

  • 1, 2, 3, 2*2= 4, 5, 2*3= 6, 7

-----------------------------------------------------------------

<u>Another solution is you divide 2100 by all numbers 1 through 9 and list those divisible:</u>

  • 2100/1 = 2100, yes
  • 2100/2 = 1050, yes
  • 2100/3 = 700, yes
  • 2100/4 = 525, yes
  • 2100/5 = 420, yes
  • 2100/6 = 350, yes
  • 2100/7 = 300, yes
  • 2100/8 = 262.5, no
  • 2100/9 = 233.33, no

So all the numbers from 1 to 7

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What is the sum of the first seven terms of the geometric series? 3 12 48 192 ...
Ad libitum [116K]

Hence, the sum of the given GP is 16347

<h2>What is a series?</h2>

a series is the cumulative sum of a given sequence of terms. Typically, these terms are real or complex numbers, but much more generality is possible.

<h3>How to solve?</h3>

we can identify from the given geomertric series.

first term = a(say) = 3

geometric factor of progression = r(say) = 4

Sum of the first 7 terms = a(\frac{r^n-1}{r-1})          ,where n is 7

Sum = 3(\frac{4^7-1}{3}) = 16348-1

       = 16347

Hence, the sum of the given GP is 16347.

to learn more about series: brainly.com/question/12578626

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