Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards
the distance between them is 476 miles, and they met 8.5hrs later
let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs
we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2
thus

solve for "r", to see how fast the cyclist was going
what about the car? well, the car's rate is r + 33.2
Ok!
1st box : 6 and 3/8
2nd box : x
3rd box : 8
Answer:
31 hours
Step-by-step explanation:
First you take 313.50 divide that by 15 get 20.9 per hour
Then you take 647.90 and divide that by 20.9
So then you're left with 31 as your answer.
The answer is 49/48. In decimal form, it is 1.02083. Hope it helps :).
Answer:
we list the number from smallest to large without for conditions like e.g 5 in hundred place and 7 in one place. therefore, 103547