I see your last line is : c(x) = 0.9(x^2-10)^2 + 101.1
Let y = x^2, then c(y) = 0.9(y-10)^2 + 101.1
Apparently, c(y) is a parabola, min is 101.1 when y = 10, max is infinity
So let x^2 = 10 -> x = sqrt(10) or -sqrt(10), min is 101.1, max is infinity
Answer:
-4 ≤ f (
) ≤ 4
Step-by-step explanation:
The range of a function is the allowed y-values of the function.
We can simply look at the periodic function below and see that the y-value ranges from a negative 4 to a positive 4. It oscillates betwen -4 and 4. That is the range.
We can say -4 ≤ f (
) ≤ 4
Last answer choice is right.
*** <u>NOTE:</u> it is a type, not "0", rather "
"
The surface of the lake.
6
5
4
3
2
1
0 Here is the surface of the lake
-1
-2
-3
-4
-5 Here is the fish
-6
2 committees. 6 is divisible by 3 twice, 8 is divisible by 4 twice.